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madreJ [45]
3 years ago
7

Is 35 miles per hour a vector or a scalar? 1. vector 2. scalar

Physics
2 answers:
elena-s [515]3 years ago
5 0

Answer:

Scalar

Explanation:

Mph, cubic feet,pounds, and hours are scalar terms

lesya692 [45]3 years ago
4 0

Answer:

scalar

is the correct answers

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A cat weighing 7 kg chases a mouse at a speed of 4 m/s. What is the kinetic energy of the cat?
jeka57 [31]
54J
You calculate kinetic energy by the equation.
KE= 1/2mv^2
m= mass
v= velocity
then we have
KE = 1/2 x 3 x 6^2
KE = 1/2 x 3 x 36 = 54J
8 0
3 years ago
Can someone help me with this really quick please
AlekseyPX

Apple juice is a homogeneous mixture. That means when you look through it, you can't see anything but  a liquid with your naked eye. The color is constant. Then how do you know there is something else in there? The color gives you the hint you need. Pure water is colorless in liquid form.

The salad dressing might be a solution and it can be made to temporarily mix when you shake it, but it will soon separate into oil and a water based acid usually vinegar.

Filtering wouldn't affect the apple juice. Whatever is in there will go through filter paper. It's like using a screen with 1 inch squares: only the largest stones would be filtered out.

Filtering might take out some of the particles in the oil / acid mixture but likely on the herbs put in. I'm not sure you should say no effect on either really.

8 0
4 years ago
Which of the following expressions gives the ratio of the energy density of the magnetic field to that of the electric field jus
miss Akunina [59]

Answer:

(d) \ \ \frac{\mu_o}{\epsilon_o} (\frac{L}{2\pi r*R} )^2

Explanation:

Energy density in magnetic field is given as;

U_B = \frac{1}{2 \mu_o} B^2

where;

B is the magnetic field strength

Energy density of electric field

U_E = \frac{1}{2}\epsilon E^2

where;

E is electric field strength

Take the ratio of the two fields energy density

\frac{U_B}{U_E} = \frac{1}{2\mu_o} B^2 / \frac{1}{2}\epsilon E^2\\\\\frac{U_B}{U_E} = \frac{B^2}{2\mu_o}  *\frac{2}{\epsilon E^2} \\\\\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{B^2}{E^2})

\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{B}{E})^2

But, Electric field potential, V = E x L = IR (I is current and R is resistance)

\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{B*L}{E*L})^2

Now replace E x L with IR

\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{B*L}{IR})^2

Also, B = μ₀I / 2πr, substitute this value in the above equation

\frac{U_B}{U_E} = \frac{1}{\mu_o \epsilon} (\frac{\mu_oI*L}{2\pi r* IR})^2

cancel out the current "I" and factor out μ₀

\frac{U_B}{U_E} = \frac{\mu_o^2}{\mu_o \epsilon} (\frac{L}{2\pi r* R})^2

Finally, the equation becomes;

\frac{U_B}{U_E} = \frac{\mu_o}{\epsilon} (\frac{L}{2\pi r*R })^2

Therefore, the correct option is (d) μ₀/ϵ₀ (L /R 2πr)²

3 0
3 years ago
the attendance qt a seminar in a year 1 was 500 in year 2 the attendance changed by 100 what was the percent change in attendanc
TiliK225 [7]
20% change from year one to year two.
5 0
4 years ago
A golf ball is whacked in a direction 25 degrees south of the east axis. The ball travels 125m. What are the east and north comp
Natalka [10]

<u>We are given:</u>

Direction of motion: 25 degrees south of the east axis

Distance covered  = 125 m

<u>East component of the Ball:</u>

<em>this component is denoted by green color in the image</em>

Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle

The magnitude of the side of the triangle on the x-axis denotes the east component of the ball

Using trigonometry, we find that the east component of the ball is:

125 * Cos(25 degrees)

125 * 0.9 = 112.5 i   (here, i denotes rightward direction on the x-axis)

<u />

<u>North Component of the Ball:</u>

<em>this component is denoted by blue color in the image</em>

Using trigonometry, we find that the North component of the ball is:

125* Sin(25 degrees)  (-j)      <em>[j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']</em>

125 * 0.42 (-j)

52.5 (-j) =   -52.5 j

Therefore the direction vector of the ball is 112.5 i - 52.5 j

<em>where 112.5 i is the East Component and -52.5 is the North Component</em>

3 0
3 years ago
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