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3 years ago

7

Is 35 miles per hour a vector or a scalar? 1. vector 2. scalar

2 answers:

elena-s [515]3 years ago

5 0

Answer:

Scalar

Explanation:

Mph, cubic feet,pounds, and hours are scalar terms

lesya692 [45]3 years ago

4 0

Answer:

scalar

is the correct answers

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A river 500 ft wide flows with a speed of 8 ft/s with respect to the earth. A woman swims with a speed of 4 ft/s with respect to

White raven [17]

Answer:

1) $\Delta s=1000\ ft$

2) $\Delta s'=998.11\ ft.s^{-1}$

3) $t\approx125\ s$

$t'\approx463.733\ s$

Explanation:

Given:

width of river, $w=500\ ft$

speed of stream with respect to the ground, $v_s=8\ ft.s^{-1}$

speed of the swimmer with respect to water, $v=4\ ft.s^{-1}$

<u>Now the resultant of the two velocities perpendicular to each other:</u>

$v_r=\sqrt{v^2+v_s^2}$

$v_r=\sqrt{4^2+8^2}$

$v_r=8.9442\ ft.s^{-1}$

<u>Now the angle of the resultant velocity form the vertical:</u>

$\tan\beta=\frac{v_s}{v}$

$\tan\beta=\frac{8}{4}$

$\beta=63.43^{\circ}$

Now the distance swam by the swimmer in this direction be d.

so,

$d.\cos\beta=w$

$d\times \cos\ 63.43=500$

$d=1118.034\ ft$

Now the distance swept downward:

$\Delta s=\sqrt{d^2-w^2}$

$\Delta s=\sqrt{1118.034^2-500^2}$

$\Delta s=1000\ ft$

2)

On swimming 37° upstream:

<u>The velocity component of stream cancelled by the swimmer:</u>

$v'=v.\cos37$

$v'=4\times \cos37$

$v'=3.1945\ ft.s^{-1}$

<u>Now the net effective speed of stream sweeping the swimmer:</u>

$v_n=v_s-v'$

$v_n=8-3.1945$

$v_n=4.8055\ ft.s^{-1}$

<u>The component of swimmer's velocity heading directly towards the opposite bank:</u>

$v'_r=v.\sin37$

$v'_r=4\sin37$

$v'_r=2.4073\ ft.s^{-1}$

<u>Now the angle of the resultant velocity of the swimmer from the normal to the stream</u>:

$\tan\phi=\frac{v_n}{v'_r}$

$\tan\phi=\frac{4.8055}{2.4073}$

$\phi=63.39^{\circ}$

Now let the distance swam in this direction be d'.

$d'\times \cos\phi=w$

$d'=\frac{500}{\cos63.39}$

$d'=1116.344\ ft$

<u>Now the distance swept downstream:</u>

$\Delta s'=\sqrt{d'^2-w^2}$

$\Delta s'=\sqrt{1116.344^2-500^2}$

$\Delta s'=998.11\ ft.s^{-1}$

3)

Time taken in crossing the rive in case 1:

$t=\frac{d}{v_r}$

$t=\frac{1118.034}{8.9442}$

$t\approx125\ s$

Time taken in crossing the rive in case 2:

$t'=\frac{d'}{v'_r}$

$t'=\frac{1116.344}{2.4073}$

$t'\approx463.733\ s$

7 0

4 years ago

Improvements in muscular strength will not affect muscular endurance.

olga2289 [7]

Answer:

the answer for your question is false ( F )

6 0

3 years ago

Calculate the magnitude of the particle accelerator's magnetic field that causes an ionized helium atom (+2q e) with a momentum

trasher [3.6K]

Answer:

The magnetic field of the particle is 1.5 T.

(C) is correct option.

Explanation:

Given that,

Momentum of particle $p=4.8\times10^{-16}\ kg m/s$

Radius = 1.0 km

Charge of the particle $q=2\times1.6\times10^{-19}\ C$

We need to calculate the magnetic field

Using relation of radius of path in magnetic field

$r=\dfrac{mv}{qB}$

Here mv = p

$B=\dfrac{p}{qr}$

Put the value into the formula

$B=\dfrac{4.8\times10^{-16}}{1000\times2\times1.6\times10^{-19}}$

$B=1.5\ T$

Hence, The magnetic field of the particle is 1.5 T.

3 0

3 years ago

Distance and direction of an objects change in position from starting point

Tju [1.3M]

Answer:

An object changes position if it moves relative to a reference point. The change in position is determined by the distance and direction of an object's change in position from the starting point (displacement). Direction • Direction is the line, or path along which something is moving, pointing, or aiming.

Explanation:

6 0

3 years ago

A machine in an ice factory is capable of exerting 3.00x10^2 N of force to pull a large block of ice up a slope. The block weigh

aivan3 [116]

Answer:

1.41 °

Explanation:

From machine,

The formula for the efficiency of machine is

E(%) = (M.A/V.R)×100................. Equation 1

Where E(%) = Percentage Efficiency of the machine, M.A = Mechanical Advantage of the machine, V.R = Velocity ratio of the machine.

Note: A slope forms an an inclined plane with the horizontal

Make V.R the subject of the equation

V.R = 100M.R/E(%)................. Equation 2

But,

M.A = L/E......................... Equation 3

Where Load, E = Effort.

Given: E = 3.00×10² N, L = 1.22×10⁴ N

Substitute into equation 3

M.A = 1.22×10⁴ / 3.00×10²

M.A = 40.7.

Note: Assuming no friction means that the efficiency of the inclined plane(slope) = 100 %

Hence, E(%) = 100 %

Substitute into equation 2

V.R = 100(40.7)/100

V.R = 40.7.

The velocity of an inclined plane is

V.R = 1/sin∅........................... Equation 4

Where ∅ = maximum angle that the slope makes with the horizontal.

make ∅ the subject of the equation

∅ = sin⁻¹(1/V.R)................... Equation 5

Substitute the value of V.R into equation 5

∅ = sin⁻¹(1/40.7)

∅ = sin⁻¹(0.0246)

∅ = 1.41 °

5 0

4 years ago

Read 2 more answers