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mario62 [17]
3 years ago
12

QUICK!!!!! QUESTION ATTACHED!!!!!!!! WILL GIVE BRAINLIEST!!!!!!!!!

Physics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

A  works to find magnitude. The leading negative sign gives us the positive magnitude after the correct velocity is found without it.

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What is most likely to happen to light that hits an opaque object?
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B. is the answer.

C is not correct because the light is actually reflected off of an opaque object.
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3 years ago
An electron is accelerated within a particle accelerator using a 100 MV electric potential. The 100 MeV electron moves along an
Delicious77 [7]

Answer:

The length of the tube is 3.92 m.

Explanation:

Given that,

Electric potential = 100 MV

Length = 4 m

Energy = 100 MeV

We need to calculate the value of \gamma

Using formula of relativistic energy

E=m_{0}c^2(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

Put the value into the formula

1.6\times10^{-15}= 9.1\times`10^{-31}\times9\times10^{16}(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)=\dfrac{1.6\times10^{-15}}{9.1\times10^{-31}\times9\times10^{16}}

Here, \gamma-1=(\dfrac{1}{\sqrt{1-\dfrac{v^2}{c^2}}}-1)

\gamma-1=0.01953

\gamma=0.01953+1

\gamma=1.01953

We need to calculate the length

Using formula of length

L'=\dfrac{L}{\gamma}

Put the value into the formula

L'=\dfrac{4}{1.01953}

L'=3.92\ m

Hence, The length of the tube is 3.92 m.

8 0
3 years ago
Which statement about an object in motion is correct? <br> Help
Nostrana [21]
Where are the statements?
7 0
3 years ago
This speed is measured with respect to the space station the spacecraft was originally launched from. In interstellar space the
valentinak56 [21]

Answer:

15193.62 m/s

Explanation:

t = Time taken = 6.5 hours

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v = Final velocity

a = Acceleration of the rocket

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{896}{1380}\\\Rightarrow a=0.6493\ m/s^2

Equation of motion

v=u+at\\\Rightarrow v=0+0.6493\times 6.5\times 60\times 60\\\Rightarrow v=15193.62\ m/s

The velocity of the rocket after 6.5 hours of thrust is 15193.62 m/s

5 0
3 years ago
What work do you think is done when you carry a 20 N weight backpack for a 1000 m walk? will the work be positive, negative, or
dezoksy [38]

The work done is positive and is equal to 20000 J

<h3>What is work done?</h3>

Work done is defined as the product of force and the distance moved by the force.

Mathematically:

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The work done by the force = 20 * 1000 = 20000J

The work done is positive and is equal to 20000 J

Learn more about work done at: brainly.com/question/25923373

#SPJ1

8 0
2 years ago
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