Pick a disease such as Multiple Sclerosis or Cerebral Palsey to be overcome.

GuDViN [60]

I know its not d but it might be c or a

5 0

3 years ago

A client has presented to the radiology department for a scheduled bronchoscopy. What drug will meet the client’s needs for amne

skelet666 [1.2K]

Answer:

First, the options:

A. Midazolam

B. Ketamine

C. Nitrous Oxide

D. Bupivacaine

The ANSWER is A.

A. Midazolam

Explanation:

A. Midazolam✔

Midazolam is mainly used for amnesia or sedation in many diagnostic, therapeutic, and endoscopic activities or procedures.

B. Ketamine ❌

It has higher risk of side effects.

C. Nitrous oxide ❌

It won't be preferable for this case, since it can not be breathed in during a bronchoscopy.

D. Bupivacaine❌

This is solely for local anesthesia.

7 0

3 years ago

An advantage of using animals from an established breeding farm over those from a breeding colony is that:

choli [55]

Answer:

Long division calculator with decimals shows the work step by step. Solve long division with decimal numbers. Calculate the quotient showing long division ...

Explanation:

Long division calculator with decimals shows the work step by step. Solve long division with decimal numbers. Calculate the quotient showing long division ...

Sorry

8 0

2 years ago

In guinea pigs hair straightness or curliness is thought to be governed by a single pair of alleles showing incomplete dominance

Nimfa-mama [501]

Answer:

Frequency of allele S is p $= 0.4939$

Frequency of allele C is q $= 0.666$

The population is not in Hardy-Weinberg equilibrium

Explanation:

Given -

Number of individuals with straight hair $= 244$

Number of individuals with curly hair $= 444$

Number of individuals with Wavy hair $= 312$

Let "p" represents the frequency for allele for straight hair and "q" represents the frequency for allele for curly hair

$p^2$ represents the frequency of genotype "SS"

$p^{2} = \frac{244}{1000} \\= 0.244$

$q^2$ represents the frequency of genotype "CC"

$p^{2} = \frac{444}{1000} \\= 0.444$

$2pq$ represents the frequency of genotype "SC"

$2pq = \frac{312}{1000} \\= 0.312$

Frequency of allele S is p

$= \sqrt{0.244} \\= 0.4939$

Frequency of allele C is q

tex]= \sqrt{0.444} \\= 0.666[/tex]

For being in Hardy Weinberg's equation-

$p+q=1\\$

Substituting the values in above equation, we get -

$0.4939+0.666\neq 1$

hence, the population is not in Hardy-Weinberg equilibrium

4 0

4 years ago

3.4 Highlight why it is important to evaluate impact assessment studies before any

Ivahew [28]

Answer:

EIA is a tool that ensures the protection and conservation of the environment and natural resources and ensures a sustainable economic development for any project under construction. ... EIA studies the effect of the surrounding environment on the project as well as the effect of the project on the surrounding environment.

hope it helps

7 0

3 years ago