means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
Uh Answer to what-
Bro you good?
Answer:
No, According to triangle Inequality theorem.
Step-by-step explanation:
Given:
Length given are 4 in., 5 in., 1 in.
We need to check whether with these lengths we can create triangular components.
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.
These must be valid for all three sides.
Hence we will check for all three side,
4 in + 5 in > 1 in. (It is a Valid Condition)
1 in + 5 in > 4 in. (It is a Valid Condition)
4 in + 1 in > 5 in. (It is not a Valid Condition)
Since 2 condition are valid and 1 condition is not we can say;
A triangular component cannot be created with length 4 in, 5 in, and 1 in by using triangle inequality theorem (since all three conditions must be valid).
Answer: Sorry
Step-by-step explanation: What table? I would love to help you but I need to see the table you are talking about. :(
