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kakasveta [241]
3 years ago
15

Why is there Roman numerals (II) in copper(II) chloride, but no (III) in Aluminum chloride?

Chemistry
2 answers:
Neporo4naja [7]3 years ago
6 0

This is because copper is a transition metals.

Transition metals don't have a definite charge, you can see this on the periodic table. However, Alkali Earth, Alkali, Metalloids, Non-metals, Halogens, Noble Gases, etc, all have a specified charge.

Although, there are exceptions: Zinc, Gold, and Cadmium.

Aluminum is a poor metal, but it has it's own charge (3+).

Therefore, Copper has roman numerals due to the fact that it's a transition metal and Aluminum is a poor metal.

Hope this helps!

Pani-rosa [81]3 years ago
5 0
There are Roman numerals in Copper Chloride because those elements are transitional metals. Aluminum is a metal. Elements that are metals and non-metals don’t use Roman numerals, but elements that are transitional metals such as Copper(II) Chloride must use Roman numerals.
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3 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
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Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

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Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

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  • <em>concentration</em>- an increase in concentration leads to more molecules available to collide and form products. An example, when you add more of indicator in a solution, the color becomes more clear since more particles react to give more color.
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Answer:

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