Two body systems that are affected by broken bone

The electronegativity values of carbon, hydrogen, and nitrogen are compared in the table.

Fofino [41]

Answer:

C. CH₄ is less than NH₃ because the NH bond is more polar than the CH bond

Explanation:

The intermolecular forces between ammonia is far stronger than for methane. Between the molecules of ammonia we have the presence of hydrogen bonds. This bond is absent in methane.

Hydrogen bonds are one of the strongest intermolecular forces. It is as a result of the electrostatic attraction between the hydrogen atom of one molecule and the electronegative atom N, O and F of another molecule.

This strong interaction is absent in methane which has just dipole - dipole attraction.

The strength of the hydrogen bond depends on the electronegativity of the combining atoms.

5 0

3 years ago

C. Use Hess's law and the following equations to calculate ΔH for the reaction 4NH3 (g) + 5O2 (g) 4NO(g) + 6H2 O(g). Show your w

Monica [59]

Considering the Hess's Law, the enthalpy change for the reaction is -906.4 kJ/mol.

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

In this case you want to calculate the enthalpy change of:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

which occurs in three stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: 2 N₂ + 6 H₂ → 4 NH₃ ΔH = –183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 2 H₂ + O₂→ 2 H₂O ΔH = -483.7 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need 4 moles of NH₃ on reactant side and it is present in first equation on product side. So you need to invert the reaction, and when an equation is inverted, the sign of delta H also changes.

Now, 4 moles of NO must be a product and is present in the second equation, so let's write this as such.

Finally, you need 6 moles of H₂O on the product side, so you need to multiply by 3 the third equation to obtain the amount of water that you need. Since enthalpy is an extensive property, that is, it depends on the amount of matter present, since the equation is multiply by 3, the variation of enthalpy also.

In summary, you know that three equations with their corresponding enthalpies are:

Equation 1: 2 4 NH₃ → N₂ + 6 H₂ ΔH = 183.6 kJ/mol

Equation 2: 2 N₂ + 2 O₂ → 4 NO ΔH = 361.1 kJ/mol

Equation 3: 6 H₂ + 3 O₂→ 6 H₂O ΔH = -1,451.1 kJ/mol

Adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O ΔH= -906.4 kJ/mol

Finally, the enthalpy change for the reaction is -906.4 kJ/mol.

Learn more about Hess's law:

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7 0

2 years ago

50 points I need help on this whole work sheet about converting moles

kozerog [31]

Answer:

Explanation:

11)

Answer:

9.08 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of O₂ = 22.7 mol

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

O₂ : P₂O₅

5 : 2

22.7 : 2/5×22.7 = 9.08

12)

Answer:

7 mol

Given data:

Number of moles of P₂O₅ = ?

Number of moles of P = 14 mol

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with P.

P : P₂O₅

4 : 2

14 : 2/4×14 = 7

13)

Answer:

76.25 mol

Given data:

Number of moles of P = 61 mol

Number of moles of O₂ react = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P with O₂.

P : O₂

4 : 5

61 : 5/4×61 = 76.25

14)

Answer:

1.25 mol

Given data:

Number of moles of P₂O₅ = 0.5 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

P₂O₅ : O₂

2 : 5

0.5 : 5/2×0.5 = 1.25

15)

Answer:

20 mol

Given data:

Number of moles of P₂O₅ = 8 mol

Number of moles of O₂ needed = ?

Solution:

Chemical equation:

4P + 5O₂ → 2P₂O₅

Now we will compare the moles of P₂O₅ with O₂.

P₂O₅ : O₂

2 : 5

8 : 5/2×8 = 20

16)

Answer:

12 mol

Given data:

Number of moles of silver made = ?

Number of moles of Ag₂O = 6 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with Ag₂O .

Ag₂O : Ag

2 : 4

6 : 4/2×6 = 12

17)

Answer:

25 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 6.25 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with O₂ .

O₂ : Ag

1 : 4

6.25 : 4×6.25 = 25

18)

Answer:

9.8 mol

Given data:

Number of moles of silver made = ?

Number of moles of O₂ produced = 2.45 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles of Ag with O₂ .

O₂ : Ag

1 : 4

2.45 : 4×2.45 = 9.8

19)

Answer:

4.4 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 2.2 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

O₂ : Ag₂O

1 : 2

2.2 : 2×2.2 = 4.4

20)

Answer:

1.5 mol

Given data:

Number of moles of silver oxide required = ?

Number of moles of O₂ produced = 0.75 mol

Solution:

Chemical equation:

2Ag₂O → 4Ag + O₂

Now we will compare the moles Ag₂O of with O₂ .

O₂ : Ag₂O

1 : 2

0.75 : 2×0.75 = 1.5

8 0

4 years ago

1 mol Fe2(CrO4)3=____g

IgorLugansk [536]

111.6g of Fe + 156g of Cr + 192g of O = 459.6g of Fe2(CrO4)3

7 0

3 years ago

A gas under an initial pressure of 0.60 atm is compressed at constant temperature from 27 L to 3.0 L. The final pressure becomes

IRINA_888 [86]

Answer: 5.4

Explanation:

P2 = P1V1/V2

P2 = (.60atm x 27L) / 3.0L = 5.4atm

8 0

3 years ago