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Allushta [10]
3 years ago
12

Do oxygen atoms become more stable or less stable when oxygen forms compounds? Explain

Chemistry
2 answers:
4vir4ik [10]3 years ago
5 0
They become more stable because they achieve a full outer shell of valence electrons with the magic number of 8.

Mademuasel [1]3 years ago
3 0
Oxygen atoms does become more stable when forming compounds as either ionic or covalent compounds are formed, leading to a full valence shell. a full valence shell is obtain due to giving (ionic) or sharing (covalent) of the electrons
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Another chem question I need help with (multiple choice)
Andreyy89

Answer:

The answer to your question is letter B, 2-methylhexane.

Explanation:

Remember that for naming organic compounds first, we need to look for the largest chain of carbons.

In your example, the largest chain is horizontal and has 6 carbons.

Later, we need to circle all the branches, in your example there is only one branch located close to the left side

After that, we number the carbons of the main chain, starting in the corner with more branches, in your example we start from the first carbon on the left.

Finally, start naming the number of the carbon branch, later hte name of the branch and finally the name of the main chain.

7 0
3 years ago
Repeating tests usually leads to
ANEK [815]

Answer:

It usually leads to more confidence in the results

4 0
3 years ago
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on a trip to italy, Cheyne rented a car to tour the country. As he turned onto the highway, he noticed that the speed limit was
rjkz [21]
 The answer is 59mph.
8 0
3 years ago
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If you have 2.4L of SO2 gas (at STP) how many moles of sulfur dioxide do you have?
Andru [333]

Answer:

0.107 mole of SO2.

Explanation:

1 mole of a gas occupy 22.4 L at standard temperature and pressure (STP).

With the above information, we can simply calculate the number of mole of SO2 that will occupy 2.4 L at STP.

This can be obtained as follow:

22.4 L contains 1 mole of SO2.

Therefore, 2.4 L will contain = 2.4/22.4 = 0.107 mole of SO2.

Therefore, 0.107 mole of SO2 is present in 2.4 L at STP.

4 0
3 years ago
In a titration experiment 12.5 ml of 0.500 m h2so4 neutralized 50.0 ml of naoh. the concentration of the naoh solution is ____.
s344n2d4d5 [400]

0.250 mol/L

<em>Step 1</em>. Write the chemical equation

H2SO4 + 2NaOH → Na2SO4 + 2H2O

<em>Step 2</em>. Calculate the moles of H2SO4

Moles of H2SO4 = 12.5 mL H2SO4 × (0.500 mmol H2SO4/1 mL H2SO4)

= 6.25 mmol H2SO4

<em>Step 3</em>. Calculate the moles of NaOH

Moles of NaOH = 6.25 mmol H2SO4 × (2 mmol NaOH/(1 mmol H2SO4)

= 12.5 mmol NaOH

<em>Step 4</em>. Calculate the concentration of the NaOH

[NaOH] = moles/litres = 12.5 mmol/50.0 mL = 0.250 mol/L

4 0
3 years ago
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