Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.
<h3>What is Solubility ?</h3>
the maximum quantity of a substance that will dissolve in a certain quantity of water at a specified temperature.
From the Solubility Graph of NaCl , we can see that the solubility of NaCl at 10 C is around 36.5gm/L.
If it is cooled down to saturation we will see the precipitate forming and that will be equal to the difference of solute present and the solubility.
As it is given that 50gm of solute is present
The precipitate will be 50- 36.5 gm, = 13.5 gm.
Therefore Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.
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