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ioda
2 years ago
10

49. How much precipitate would result if you have 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation

Chemistry
1 answer:
Gennadij [26K]2 years ago
7 0

Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.

<h3>What is Solubility ?</h3>

the maximum quantity of a substance that will dissolve in a certain quantity of water at a specified temperature.

From the Solubility Graph of NaCl , we can see that the solubility of NaCl at 10 C is around 36.5gm/L.

If it is cooled down to saturation we will see the precipitate forming and that will be equal to the difference of solute present and the solubility.

As it is given that 50gm of solute is present

The precipitate will be 50- 36.5 gm, = 13.5 gm.

Therefore Option D is the correct answer , 13.5gm of precipitate would result if 50 grams of NaCl at 10 degrees Celsius and its cooled to saturation.

To know more about Solubility

brainly.com/question/8591226

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How many grams of magnesium acetate are in 8.95x10^23 formula units?
Natasha_Volkova [10]

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211.63 g.

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  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:  </u></em>

1.0 mole → 6.022 x 10²³ molecules.

??? mole → 8.95 x 10²³ molecules.

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3 years ago
A package contains 1.33 lb of ground round. If it contains 29% fat, how many grams of fat are in the ground round? The book is s
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To obtain the grams of fat that the ground round has, knowing that it weighs 1.33 pounds we must pass this value to grams. Since 1 pound equals 453.59 grams, 1.33 pounds equals 603.27 (453.59 x 1.33).

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In this way, your reasoning is correct and it is probably a mistake in the book.

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