<h3>
Answer: C) 2 km west</h3>
Explanation:
With displacement, all we care about is the beginning and end. We don't care about the middle part(s) of the journey. So we'll take the straight line route from beginning to end when it comes to computing displacement.
We start at A(0,0) and end at B(-2,0). Going from A directly to B has us go 2 km west. Keep in mind that displacement is a vector, so you must include the direction along with the distance.
Answer:
Step-by-step explanation:
in this case, 
is your number. we will always note square with the tiny two at the top of the number.
Four less than anything is easily shown with a minus four.
eg. four less of 12 square:
= :)
X = (2^2)^(2.5)
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32
</span>y^(-3/2) = 125
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
Answer:
The distance between the astronomers and the moon was ![7.56*10^{8]](https://tex.z-dn.net/?f=7.56%2A10%5E%7B8%5D)
meters.
Step-by-step explanation:
We have that the speed is the distance divided by the time, so:
In this problem, we have that:
The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that 
.
If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?
We have that 
m/s.
We have to find d. So:
The distance between the astronomers and the moon was meters.
Answer:
using a negative facto to factor the expression will be:
- 7a+49b - 35 = -7(a-7b+5)
Step-by-step explanation:
Given the expression
- 7a+49b - 35
Rewrite -35 as 5 · 7
Rewrite 49 as 7 · 7
so
= -7a + 7 · 7b - 5 · 7
as -7 is the common factor, so factoring out
= -7(a-7b+5)
Thus, using a negative facto to factor the expression will be:
- 7a+49b - 35 = -7(a-7b+5)
