All categories

3 years ago

Provide at least three indicators of a chemical change that are present in burning a piece of paper.

Chemistry

1 answer:

Pie3 years ago

3 0

Answer:

Some chemical indicators perceived while a piece of paper is burning are:

Production of an Odor: there is a smell of burnt paper

Change in Temperature: combustion is a highly exothermic reaction , so the temperature increase

Change in Color: paper changes to ashes as the burning process occurs

You might be interested in

Boyle's Law Problems Charles' Law Problems

zysi [14]

Answer:

here are the answers babe. Feel free to ask for more

8 0

3 years ago

Select all the correct answers

Alborosie

Answer:

Explanation:

4 0

3 years ago

In the Northern Hemisphere, recall that atmospheric CO2 levels are highest in early spring and lowest during early fall. What ac

asambeis [7]

Answer:

Photosynthesis

Explanation:

Photosynthesis can be defined as the process whereby plants, some protistans, and some bacteria utilize the energy from sunlight to produce glucose from water and carbon dioxide. In early spring, there is the shift of plants from scanty winter branches to abundant spring leaves. When the leaves on the trees reduced in the fall, dead plants break down throughout the winter due to the activities of microbes. The microbes decompose the plant materials and generate carbon dioxide. This leads to increase in the level of carbon dioxide in the atmosphere. In the spring, leaves return to the plants/trees and the rate of photosynthesis increases greatly. This consumes more carbon dioxide and the level of carbon dioxide in the atmosphere reduced.

4 0

3 years ago

In the first 15.0 s of the reaction, 1.7×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.440 L . What is the

Step2247 [10]

Answer:

$Rate=2.57x10^{-3}\frac{M}{s}$

Explanation:

Hello,

In this case, for the reaction:

$2N_2O(g) \rightarrow 2N_2(g)+O_2(g)$

We can easily compute the average rate by firstly computing the final concentration of oxygen:

$[O_2]=\frac{0.017mol}{0.440L}=0.0386M$

Then, we compute it by using the given interval of time: from 0 seconds to 15.0 seconds and concentration: from 0 M to 0.0386M as oxygen is being formed:

$Rate=\frac{0.0386M-0M}{15.0s-0s}\\ \\Rate=2.57x10^{-3}\frac{M}{s}$

Regards.

8 0

4 years ago

3. The molar heat of solution for ammonium nitrate (NH 4 NO 3 ) is 25.7 kJ/mol.

Karo-lina-s [1.5K]

Answer:

3.42 moles

Explanation:

By the law of conservation of energy, assuming no losses of heat to the surroundings, the amount of heat consumed by the dissolution of the ammonium nitrate is equal to the amount of heat released from the water. This is, the ammonium nitrate absorbs all the heat it needs to break the ions apart and get dissolved from the water in which it is being dissolved.

Thus:

88.0kJ = n × 25.7 kJ/mol

↑ ↑ ↑

heat released number of moles molar heat of solution

from water of NH₄NO₃ for NH₄NO₃

Solve for n and compute:

n = 88.0kJ / (25.7kJ/mol) = 3.42 moles ← answer

7 0

3 years ago