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Digiron [165]
3 years ago
10

2.Which term best describes the processes that change rocks and mountains on Earth’s surface over time?

Chemistry
1 answer:
ArbitrLikvidat [17]3 years ago
4 0

Answer:

B. weathering

or erosion

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What characteristic frequencies in the infrared spectrum of your sodium borohydride reduction product will you look for to deter
kkurt [141]

Answer:

A)The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

B)Characteristic frequency  present in the infrared spectrum will be at a peak of  3300-3400 cm-1 which will be due to O-H stretch.

C)If the product is wet with water there will be no change in the infrared spectrum

Explanation:

The characteristic frequency to look out for is  1720-1740 cm-1 (for C=O) for which will disappear in the end product but initially present in the reactant.

Characteristic frequency  present in the infrared spectrum will be at a peak of 3300-3400 cm-1 which will be due to O-H stretch.

If the product is wet with water there will be no change in the infrared spectrum

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<span>the elements in groups1a, 2a, 3a have positive charges according to their group numbers</span>
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Ten possibilities for staving off catastrophic climate change ... What can one person, or even one nation, do on their own to slow and reverse climate change? ... could reduce greenhouse gas emissions to safer levels—there are ... mode of transport that does not require anything other than human energy.

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6 0
3 years ago
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Balancing chemical equations
mojhsa [17]

<span>2H2 + O2 → 2H2O</span>

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4 0
4 years ago
Having been heated to 800 K , at some point the tank starts to leak. By the time the leak is repaired, the tank contains only ha
Liula [17]

Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

Applying Charles Law

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Initial volume V1 = 1

Final volume V2 = 1/2 (halved)

Initial temperature T1 =800K

Final temperature T2 = ?

(1/800) = (1/2)/T2

T2 = 800/2

T= 400K

Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0
3 years ago
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