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3 years ago

What is the molar mass of glucose (C6H12O6)??

Chemistry

1 answer:

Over [174]3 years ago

8 0

C6H12O6 = 12 x 6 + 1 x 12 + 16 x 6 => 180 g/mol

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The summary or ending of your experiment

Katyanochek1 [597]

Answer:

Conclusion

Explanation:

I believe you were asking for the term that best matches with the description given. Typically the conclusion summarizes your experiment in a 1 to 2 paragraph format.

7 0

3 years ago

1 A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circul

LenKa [72]

The correct answer to this question is that the length of 14 is it’s half Which would be 7

6 0

2 years ago

1 C8H10(l) +21/2O2(g) → 8CO2(g) + 5H2O(g), Hcomb= ? Hf for C8H10(l) = +49.0kJ/mol C8H10(l) Use the balanced combustion reaction

nikklg [1K]

Answer:

$H_{comb}=-4406kJ/mol$

Explanation:

Hello,

In this case, the enthalpy of combustion is understood as the energy released when one mole of fuel, in this case octene, is burned in the presence of oxygen and is computed with the enthalpies of formation of the fuel, carbon dioxide and water as shown below (oxygen is circumvented as it is a pure element):

$H_{comb}=8*\Delta _fH_{CO_2}+5\Delta _fH_{H_2O}-\Delta _fH_{C_8H_{10}}$

Thus, since we already know the enthalpy of combustion of the fuel, for carbon and water we have -393.5 and -241.8 kJ/mol respectively, thereby, the enthalpy of combustion turns out:

$H_{comb}=8*(-393.5kJ/mol)+5(-241.8kJ/mol)-49.0kJ/mol\\\\H_{comb}=-4406kJ/mol$

Best regards.

4 0

3 years ago

Phase changes!a. Write out the Clapeyron equation and explain what it describes.b. Write out the Clausius-Clapeyron equation and

djverab [1.8K]

Answer:

Solutions in the attachment.

Explanation:

4 0

3 years ago

When iron metal reacts with oxygen, the reaction can form Fe2O3. Write a balanced chemical equation for this reaction, and find

ryzh [129]

The balanced equation is
4Fe+3O₂⇒2Fe₂O₃

We know that the mole of Fe₂O₃ is 6, and since the ratio between oxygen and Fe₂O₃ is 3:2, we can see that

3:2 = x:6 (3 oxygen moles can make 2 Fe₂O₃ moles = x oxygen moles can make 6 Fe₂O₃ moles)

Multiply outside and inside (3*6 , 2*x) and put them on opposing sides of the equation

2*x = 3*6
2x=18
x=9
Therefore 9 moles of oxygen is needed.

6 0

3 years ago

Read 2 more answers