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Brilliant_brown [7]
3 years ago
11

2.

Chemistry
2 answers:
Ostrovityanka [42]3 years ago
4 0

Answer:

Explanation: was given the equation: Ca(OH)2 + H3PO4 --> H2O + Ca3(PO)4, which I balanced to:

3 Ca(OH)2 + 2 H3PO4 --> 6 H2O + Ca3(PO)4

I am supposed to find

a) How many grams of calcium phosphate are produced from the reaction of 25.0g of Ca(OH)2 with excess H3PO4.

b) If 0.139 moles of Ca(OH)2 react with 0.58 moles H3PO4, determine the grams of H2O produced and the grams of the excess reagent left after the reaction.

almond37 [142]3 years ago
4 0

was given the equation: Ca(OH)2 + H3PO4 --> H2O + Ca3(PO)4, which I balanced to:

3 Ca(OH)2 + 2 H3PO4 --> 6 H2O + Ca3(PO)4

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If there is a 2 kg ball with the same kinetic energy which one will be moving faster
Andrew [12]

Answer:

If you double the mass of an object, you double the kinetic energy. If you double the speed of an object, the kinetic energy increases by four times. The word "kinetic" comes from the Greek word "kinesis" which means motion. Kinetic energy can be passed from one object to another in the form of a collision.

Explanation:

6 0
3 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

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5 0
3 years ago
The production of ethylene glycol from ethylene chlorohydrin and sodium bicarbonate ↑ is carried out in a semibatch reactor. A 1
jarptica [38.1K]

Answer:

The constant density decreases

Explanation:

As the temperature of a solvent increases, the solubility of any gas dissolved in that solvent decreases.

For example:

when the temperature of a river, lake or stream is raised high , due to discharge of hot water from some industrial process the solubility of the oxygen in the water is decreased .The fish and the other organisms that live in the water bodies such as rivers, ponds, lakes etc can survive only in the presence of oxygen and decrease in the concentration of the water due to increased temperature can lead to the death of the fish and this may in turn damage the ecosystem.

In the above example, water is considered as the solvent and the oxygen is considered as the solute. When the temperature of the solvent that is water increases, the solubility of the gas that is oxygen in the solvent decreases.

Therefore the answer is decreases

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Answer:

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Explanation:

Please see the step-by-step solution in the picture attached below.

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Please Help Weak Acid Base Problems!!!
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Answer:

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