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evablogger [386]
2 years ago
11

1 A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circul

ar cross -section diameter d = 7 cm. The reservoirs are open to the atmosphere at an ambient temperature of 20 C. The difference in elevation between the free surface can be accounted for by the local loss coefficients Kentrance  Kexit 1.0, Kelbow 0.4. If the volumetric flow rate in the system Q = 10 Liter/s, and the surface roughness of the pipe is  = 0.15 mm, calculate:
(a) The average water flow velocity in the pipe.
Chemistry
1 answer:
LenKa [72]2 years ago
6 0
The correct answer to this question is that the length of 14 is it’s half Which would be 7
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At 700 K, CCl4 decomposes to carbon and chlorine. The Kp value for the decomposition is 0.76. Find the starting pressure of CCl4
ASHA 777 [7]

Answer: The starting pressure of CCl_4 is 1.39 atm.

Explanation:

   CCl_4\rightleftharpoons C(s)+ 2Cl_2

Initial  p                     0  0

eq'm   p-x                    0  2x  

Total pressure at equilibrium = p - x + 2x = p + x = 1.9...(1)

K_p=0.76=\frac{p_{C}\times p^2_{Cl_2}}{p_{CCl_4}}=\frac{0\times(2x)^2}{p-x}

K_p=0.76=\frac{4x^2}{p-x} ...(2)

Solving equation (1) and (2). we get x = 0.51

p + x = 1.9

p= 1.9 - 0.51 = 1.39 atm

The starting pressure of CCl_4 is 1.39 atm.

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2 years ago
A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
Butoxors [25]

Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
2 years ago
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