3 years ago

Find the y-intercept of the parabola y=x^2+4x

Mathematics

1 answer:

marysya [2.9K]3 years ago

4 0

Answer:

x= -4

x= 0

(-4,0)

(0,0)

minimum= (-2,-4)

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35 points + brainliest!

jarptica [38.1K]

Answer:

x= -2-√11. or. x= -2 + √11

Step-by-step explanation:

solving quadratic equation by completing the square

x^2+4x-7=0

x^2+4x=7

x^2+4x + (4/2)^2=7 + (4/2)^2 ( adding (1/2 coefficient of x)^2 on both sides

x^2+4x + 4=7 + 4

x^2+4x + 4=11. factorize(x^2+4x + 4) into (x + 2)^2

(x + 2)^2=11

√(x + 2)^2= + - √11

x + 2 = + - √11

there are two different solution .

x + 2 = -√11. or x + 2 = + √11.

x= -2-√11. or. x= -2 + √11.

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Answer:

Step-by-step explanation:

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(15 points + Brainliest) Help solve the following geometry proof in the image, there can be as many statements and reasons.

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Two numbers, a and b, are stored in one byte floating point notation using the least significant (rightmost) 3 bits for the expo

ehidna [41]

$a=00110111 = 00110_2 \times 2^{111_2} = 6 \times 2^{-1} = 3$

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Hard to select the correct answers without seeing the choices. Let's check a couple,

$11111001 = -(00000+1) \times 2^{1} = -2 \quad\checkmark$

$11110000 = -(00001 + 1) \times 2^{0} = -2 \quad\checkmark$

$11100111 = -(00011 + 1) \times 2^{-1} = -4/2= -2 \quad\checkmark$

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Answer:

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Step-by-step explanation:

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