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harina [27]
4 years ago
11

State Faraday's law in words

Physics
1 answer:
snow_tiger [21]4 years ago
5 0
The induced electromotive force in any closed circuit is equal to the negative of the time rate of change of the magnetic flux enclosed by the circuit. That is the textbook definition that is widely accepted.
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С
Lelechka [254]

Answer:

a = 0.8 [m/s²]

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force on a body is equal to the product of mass by acceleration, in this way we come to the following equation:

∑F = m*a

where:

F = forces applied [N]

m = mass = 1000 [kg]

a = acceleration [m/s²]

Now using Newton's second law.

1200 - 400 = 1000*a\\800 = 1000 *a\\a=0.8[m/s^{2} ]

8 0
3 years ago
Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.
viva [34]

In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.

In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.

<h3>What is science laboratory?</h3>

The science lab is a place where the experiments related to the science background are performed with the use of apparatus.

The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.

Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.

Learn more about science laboratory.

brainly.com/question/7412101

#SPJ2

8 0
2 years ago
Read 2 more answers
If a soccer ball takes 20 seconds to roll 10 meters, what is the average speed of the soccer ball?
xxTIMURxx [149]
2 Seconds per 1 meter
5 0
3 years ago
What are the four layers of oceanic crust from top to bottom?
Thepotemich [5.8K]
Oceanic, Crust, Geolific, techtonic
7 0
3 years ago
The electric field strength is 5.50×10^4 N/C inside a parallel-plate capacitor with a 2.50 mm spacing. A proton is released from
valentina_108 [34]

Answer:

v=1.6\times10^{5}m/s

Explanation:

The equation that relates electric field strength and force that a charge experiments by it is F=qE.

Newton's 2nd Law states F=ma, which for our case will mean:

a=\frac{F}{m}=\frac{qE}{m}

We know from accelerated motion that v^2=v_0^2+2ad

In our case the proton is released from rest, so v_0=0m/s and we get v=\sqrt{2ad}

Substituting, we get our final velocity equation:

v=\sqrt{\frac{2qEd}{m}}

For the <em>proton </em>we know that q=1.6\times10^{-19}C and m=1.67\times10^{-27}kg. Writing in S.I. d=0.0025m, we obtain:

v=\sqrt{\frac{2(1.6\times10^{-19}C)(5.5\times10^{4}N/C)(0.0025m)}{(1.67\times10^{-27}kg)}}=162318.5m/s=1.6\times10^{5}m/s

6 0
3 years ago
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