Answer:
Mix
Explanation:
A battery has two electrodes, at one end it has the anode and the other end has the cathode. Electrons travel through the circuit from the anode (negative) to the cathode (positive), and this is the driving force that provides electricity to flow through circuits.
The anode needs to have a low electron affinity because it needs to readily release electrons, and the cathode needs to have a high electron affinity because it needs to readily accept electrons.
Answer:
E = 401.3 eV
Explanation:
As we know that the thinnest gap in the direction of metal is given as
so here we can say that lowest energy of photon will not able to break this electron from above thickness
so we will have
here we have
also we have
so we will have
Answer:
Chromosphere
Explanation:
The Chromosphere is one of the important internal layers of the sun, which lies above the layer of Photosphere. The Chromosphere has a thickness of about 3 to 5 km having a very high temperature, ranging from about 5000 to 20,000°C. Due to this extreme temperature and continuous nuclear fusion process that takes place at the core of the sun, there forms the reddish colored layer, which is usually not visible but can be observed during the time of a total solar eclipse, by the use of an ultraviolet telescope.
75 because 25 plus 75 equals 90
Answer:
<em>The velocity of the camera just before it hit the ground = 35.97 m/s.</em>
Explanation:
Velocity: This can be defined as the ratio of the displacement of a body to the time. Velocity is a vector quantity, and as such it can be represented both in magnitude and direction.
From the equation of motion,
v² = u² + 2gs ................ Equation 1
Where v = final velocity, u = initial velocity, g = acceleration due to gravity, s = distance.
Note: Before the velocity of the camera before it hits the ground = The final velocity of the camera.
<em>Given: u = 10.8 m/s, s = 60 m. g = 9.81 m/s.</em>
<em>Substituting into equation 1,</em>
<em>v² = 10.8² + 2(9.81)(60)</em>
<em>v² = 116.64+1177.2</em>
<em>v² = 1293.84 </em>
<em>v = √(1293.84)</em>
<em>v = 35.97 m/s.</em>
<em>Hence the velocity of the camera just before it hit the ground = 35.97 m/s.</em>
