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2 years ago

A 75N force is applied to a 15kg box. If the box

Physics

1 answer:

icang [17]2 years ago

6 0

Answer:

The coefficient of kinetic friction is 0.51.

Explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient of kinetic friction. It is given by the formula as follows :

$F=\mu_k F_N$

Where,

$F_N=mg$ , is the normal force

$\mu_k=\dfrac{F}{mg}\\\\\mu_k=\dfrac{75}{15\times 9.8}\\\\\mu_k=0.51$

So, the coefficient of kinetic friction is 0.51.

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Water flows through a horizontal pipe with a cross-sectional area of 3mat a speed of 10 m/s with a pressure of 3 Bars at a Point

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(a) The speed of the water at point B is 10 m/s and the speed at point C is 5 m/s.

(b) The pressure of the water at point B is 4.96 bars and the pressure at point C is 5.335 bars.

<h3>Speed of the water at point B </h3>

The speed of the water at point B is determined from continuity equation as shown below;

Q = AV

A₁V₁ = A₂V₂

Since, A₁ = A₂ = 3 m²

V₁ = V₂ = 10 m/s

Thus, the speed of the water at point B is 10 m/s.

<h3>Speed of water at point C</h3>

A₁V₁ = A₃V₃

A₁V₁ = (2A₁)V₃

V₃ = (A₁V₁) / 2A₁

V₃ = V₁ / 2

V₃ = 10/2

V₃ = 5 m/s

Thus, the speed of the water at point C is 5 m/s.

<h3>Pressure of the water at point B </h3>

The pressure of the water at point B is determined by appying Bernoulli's equation as shown below;

P₁ + ¹/₂ρV₁² + ρgh₁ = P₂ + ¹/₂ρV₂² + ρgh₂

where;

P₁ = 3 bars = 300,000 Pa
ρ density of water = 1000 kg/m³
g is acceleration due to gravity = 9.8 m/s²

300,000 + ¹/₂(1000)(10)² + (1000)(9.8)(20) = P₂ + ¹/₂(1000)(10)²

546,000 = P₂ + 50,000

P₂ = 496,000 Pa

P₂ = 4.96 bars

<h3>Pressure of the water at point C</h3>

P₁ + ¹/₂ρV₁² + ρgh₁ = P₃ + ¹/₂ρV₃² + ρgh₃

546,000 = P₃ + ¹/₂(1000)(5)²

546,000 = P₃ + 12,500

P₃ = 533,500 Pa

P₃ = 5.335 bars

Learn more about pressure in horizontal pipe here: brainly.com/question/26761275

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