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sergey [27]
2 years ago
12

A 75N force is applied to a 15kg box. If the box

Physics
1 answer:
icang [17]2 years ago
6 0

Answer:

The coefficient  of kinetic friction is 0.51.

Explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient  of kinetic friction. It is given by the formula as follows :

F=\mu_k F_N

Where,

F_N=mg, is the normal force

\mu_k=\dfrac{F}{mg}\\\\\mu_k=\dfrac{75}{15\times 9.8}\\\\\mu_k=0.51

So, the coefficient  of kinetic friction is 0.51.

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A car is traveling at 24.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant accelerat
Elan Coil [88]

Answer:

The answer to your question is : vf = 15.18 m/s

Explanation:

Data

vo = 24 m/s

d = 120 m

vf = ? when d = 60.0 m

Formula

              vf² = vo²  + 2ad

For d =100m

            a = (vf² - vo²) / 2d

            a = (0 -24²) / 2(100)

            a = -576/200

             a = 2.88 m/s²

Now, when d = 60

        vf² = (24)² - 2(2.88)(60)

        vf² = 576 - 345.6

        vf² = 230.4

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4 0
3 years ago
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Art [367]

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2 years ago
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Throw a paper ball towards a hard wall.
Len [333]
The answer is d hope this helps
7 0
3 years ago
What is the speed of a sound wave that takes 0.5 s to travel 750 m?
kvasek [131]

Answer:

C. 1500.

Explanation:

750 / .5 = 1500.

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4 0
3 years ago
A 72-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.
Shalnov [3]

Answer:

Explanation:

During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s

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During the acceleration in upward direction , let reaction force of ground on man be R .

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R - mg = ma

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