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sergey [27]
2 years ago
12

A 75N force is applied to a 15kg box. If the box

Physics
1 answer:
icang [17]2 years ago
6 0

Answer:

The coefficient  of kinetic friction is 0.51.

Explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient  of kinetic friction. It is given by the formula as follows :

F=\mu_k F_N

Where,

F_N=mg, is the normal force

\mu_k=\dfrac{F}{mg}\\\\\mu_k=\dfrac{75}{15\times 9.8}\\\\\mu_k=0.51

So, the coefficient  of kinetic friction is 0.51.

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