A 75N force is applied to a 15kg box. If the box
1 answer:
Answer:
The coefficient of kinetic friction is 0.51.
Explanation:
Given that,
Applied force, F = 75 N
Mass of a box, m = 15 kg
The acceleration of the box is 3 m/s²
We need to find the coefficient of kinetic friction. It is given by the formula as follows :
Where,
, is the normal force
So, the coefficient of kinetic friction is 0.51.
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The wind tunnel speed that must be used to test the car 1 / 5 model of a car that normally runs at 30 mph is 150 mph
Re = u L / ν
Re = Reynold's number
u = Flow speed
L = Characteristic linear dimension
ν = Kinematic viscosity
ν = 1.516 *
m² / s
ν = ν
= 1.516 *
m² / s
L = L
/ 5
u = 30 mph
Re = u
L
/ 5 * 1.516 *
Re = 30 L
/ 1.516 *
In tunnel,
Re = Re
u L
/ 5 * 1.516 *
= 30 L
/ 5 * 1.516 *
u = 30 * 5
u = 150 mph
Therefore, the wind tunnel speed that must be used to test the car is 150 mph
To know more about Reynold's number
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