Question

A 75N force is applied to a 15kg box. If the box

Answer 1

Answer:

The coefficient  of kinetic friction is 0.51.

Explanation:

Given that,

Applied force, F = 75 N

Mass of a box, m = 15 kg

The acceleration of the box is 3 m/s²

We need to find the coefficient  of kinetic friction. It is given by the formula as follows :

$F=\mu_k F_N$

Where,

$F_N=mg$, is the normal force

$\mu_k=\dfrac{F}{mg}\\\\\mu_k=\dfrac{75}{15\times 9.8}\\\\\mu_k=0.51$

So, the coefficient  of kinetic friction is 0.51.