Answer:
isn't understand this question please classify
No. of students playing at least one game = 44
Step-by-step explanation:
B = basketball; V = volleyball
n(B) = no of students playing only B
n(V) = no. of students playing only V
n(B∩V) = no. of students playing both B and V
Now:
32 students play basketball. Some of them could also be playing volleyball. Hence, the number of students playing only basketball will be 32 minus those that play both.
n(B) = 32 - 13 ............(Given that 13 play both games)
n(B) = 19
Similarly,
25 students play volleyball. Some of them could also be playing basketball. Hence, the number of students playing only volleyball will be 25 minus those that play both.
n(V) = 25 - 13
n(V) = 12
Thus, we have 19 students playing only B, 12 students playing only V and 13 students playing BOTH.
Clearly, the number of students that play at least one game is:
No. of students playing ONLY basketball +
No. of students playing ONLY volleyball +
No. of students playing BOTH
This can be given as:
n(B) + n(V) + n(B∩V)
= 19 + 12 + 13
= 44
Y = -1/2x + 4
X + 2y = -8
Replace y in the second equation with the first one:
X + 2(-1/2x +4)=-8
Simplify:
X -X +8 = -8
Simplify:
8 = -8
Subtract 8 from both sides:
0 = -16
This is a false statement, so there are no solutions.
Direct variation is of the form: y=kx (inverse variation is of the form y=k/x)
Assuming that k is positive :)
y increases as x increases and y decreases as x decreases. There is a direct ratio that is described by k. k=y/x.