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trapecia [35]
3 years ago
11

Find the least common multiple of 10 and 14.

Mathematics
2 answers:
aksik [14]3 years ago
8 0
We can do this by just adding 14 to 14 until we get a number that is divisible by 10.  We can do it this way because it will be a small number.  Let's list them out.  14, 28, 42, 56, 70.  70 is divisible by 10, so 70 is the answer.
fredd [130]3 years ago
7 0
The least common multiple of them both (10 and 14) would be 70!
Now to break it down a little for the people in the back -
10's least common multiples go a little like this.. 60, 70, 80- etc.
While 14's least common multiples are 56, 70, 84, etc.
Which number is in common ? 70! (:
I hope all is well, and you pass! Good luck, rockstar!
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A rival chocolate company is larger. They have 14 times as many workers.
OLga [1]

Answer:

you need to tell us the entire question

Step-by-step explanation:

8 0
3 years ago
PT=y,TR=x+3,QT=2y,TS=3x-1 I'm confused and u really need help. My teacher isn't the greatest and wasn't much help.
PtichkaEL [24]

Answer:

y=10, x=7

Step-by-step explanation:

Since the diagonals of a parallelogram bisect each other, PT should be equal to TR and QT should be equal to TS. So, y=x+3 and 2y=3x-1. Multiplying the first equation by 3 gives you 3y=3x+9. Using elimination to subtract these two equations gives you y=10. And since y=x+3, substitute y=10 there. 10=x+3, x=7.

3 0
3 years ago
Determine if true:<br> 2x6-3=10
cestrela7 [59]

Answer:

False

Step-by-step explanation:

2x6=12

2x6=1212-3=9

Hence, the equation is false.

4 0
2 years ago
Read 2 more answers
Solve for x: 1 &lt; x + 3 &lt; 4
MrRa [10]
It’s clearly number 2. 3 and 4 don’t have a 4 so it leaves 1 and 2 1 has gt so that’s wrong so it’s 2 because it has lt
4 0
2 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
1 year ago
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