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GrogVix [38]
3 years ago
14

Solve the system of equations. x+2y=6; 3x-14y=8 please help

Mathematics
1 answer:
ira [324]3 years ago
8 0
Let x = 6 = 2y so
3(6 - 2y) + 14y = 8 so
18 - 6y + 14y = 8 so
8y = -10 and
y =  \frac{ - 10}{8} =   - \frac{5}{4}  \\  \\ since \: x = 6 - 2y \\ 6  - 2( \frac{ - 5}{4}) = x  \: so \\ x = 6 +  \frac{10}{4} =  \frac{24}{4} +  \frac{10}{4} =  \frac{34}{4} =  \frac{17}{2}

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Murrr4er [49]

Answer:

9 cans of soup and the 4 frozen dinners were purchased

Step-by-step explanation:

Let x represent the number of cans of soup purchased.

Let y represent the number of frozen dinners purchased.

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x + y = 13

Each can of soup has 250 mg of sodium and each frozen dinner has 550 mg of sodium. The 13 cans of soup and frozen dinners which he purchased collectively contain 4450 mg of sodium. This means that

250x + 550y = 4450 - - - - - - - - -1

Substituting x = 13 - y into equation 1, it becomes

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