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GrogVix [38]
3 years ago
14

Solve the system of equations. x+2y=6; 3x-14y=8 please help

Mathematics
1 answer:
ira [324]3 years ago
8 0
Let x = 6 = 2y so
3(6 - 2y) + 14y = 8 so
18 - 6y + 14y = 8 so
8y = -10 and
y =  \frac{ - 10}{8} =   - \frac{5}{4}  \\  \\ since \: x = 6 - 2y \\ 6  - 2( \frac{ - 5}{4}) = x  \: so \\ x = 6 +  \frac{10}{4} =  \frac{24}{4} +  \frac{10}{4} =  \frac{34}{4} =  \frac{17}{2}

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5x9= 45 remainder3 which means it 9 3/5
5 0
3 years ago
Please help and explain.
Agata [3.3K]

Piecewise functions have different definitions, depending on when you evaluate them.

Given an input x, your function returns:

  • 2x if the input is negative
  • 1 if the input lies between 0 (included) and 2 (excluded)
  • the square root of x if the input is greater than 2 (included)

You want to know what f(0) is. In other words, you want to know what happens if we give 0 as input.

The piecewise definition tells us that, if the input is 0, the function outputs 1.

So, you have f(0) = 1.

4 0
3 years ago
Pepper jackie purchased 5.8 kg of rainbow sprinkles. If she divides them equally into 8 star containers, how much will be in eac
inysia [295]

0.725kg or 725 grams


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3 years ago
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Irina18 [472]
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6 0
3 years ago
Read 2 more answers
What is the perimeter of a polygon with verticals at (-1, 3) , (-1, 6) , (2, 10) , (5, 6) , and (5, 3)
Marat540 [252]

Answer:

22 units

Step-by-step explanation:

The perimeter of a polygon is said to be the sum of the length of it's sides.

From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are

A = (−1, 3)

B = (−1, 6) ​

C = (2, 10)

D = (5, 6) ​​

E = (5, 3) ​

To find the distance between two points, we use the formula

d = √[(y2 - y1)² + (x2 - x1)²]

Between A and B, we have

d(ab) = √[(6 - 3)² + (-1 --1)²]

d(ab) = √(3²) + 0

d(ab) = √9 = 3

Between B and C, we have

d(bc) = √[(10 - 6)² + (2 --1)²]

d(bc) = √[4² + 3²]

d(bc) = √(16 + 9) = √25 = 5

Between C and D, we have

d(cd) = √[(6 - 10)² + (5 - 2)²]

d(cd) = √[(-4)² + 3²]

d(cd) = √(16 + 9) = √25 = 5

Between D and E, we have

d(de) = √[(3 - 6)² + (5 - 5)²]

d(de) = √(-3)² + 0

d(de) = √9 = 3

Between E and A, we have

d(ea) = √[(3 - 3)² + (5 --1)²]

d(ea) = √[0 + (6)²]

d(ea) = √36 = 6

The perimeter is given as

d(ab) + d(bc) + d(cd) + d(de) + d(ea) =

3 + 5 + 5 + 3 + 6 = 22 units

7 0
3 years ago
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