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4 years ago

What happens when a constant force is applied to an object

Physics

1 answer:

nignag [31]4 years ago

3 0

Answer:

Newton's second law says that when a constant force acts on a massive body, it causes it to accelerate, i.e., to change its velocity, at a constant rate. In the simplest case, a force applied to an object at rest causes it to accelerate in the direction of the force.

Explanation:

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when an object is charged by contact, how does the kind of charge transferred compare to that on the object giving the charge?

11111nata11111 [884]

Lets say sphere 1 has a charge of 12 + and sphere 2 has a charge of 0 +. After they are touched Sphere 1 becomes 6 + and sphere 2 6 +. So 6 - 12 = a change of 6 -, while 6 - 0 = a change of 6 + Therfore,

Answer: The sign of the charge change / transfered are opposites.

8 0

3 years ago

An electron is in a vacuum near Earth's surface and located at y = 0 m on a vertical y axis. At what value of y should a group o

Bingel [31]

Answer:

the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

Explanation:

As we know that the gravitational force on electron at y = 0 is counter-balanced by the weight of the electron

So we have

$\frac{kq_1q_2}{r^2} = mg$

here we have

$q_1 = e$

$q_2 = 23 e$

$m = 9.11 \times 10^{-31} kg$

also we know that

$e = 1.6 \times 10^{-19} C$

so we will have

$\frac{(9\times 10^9)(1.6 \times 10^{-19})(23\times 1.6 \times 10^{-19})}{r^2} = (9.11 \times 10^{-31})(9.81)$

$\frac{5.3 \times 10^{-27}}{r^2} = 8.94 \times 10^{-30}$

$r = 24.35 m$

so the bunch of 23 electrons must be placed on y axis at coordinate y = - 24.35 m.

7 0

3 years ago

Bile helps in the digestion of —————-

Gnoma [55]

Answer:

Bile helps in the digestion of fats

4 0

3 years ago

Read 2 more answers

A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a

aliya0001 [1]

Answer:

$P_2 = -1.9 \times 10^8 Pa$

Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

$Q = A_1v_1 = A_2v_2$

at the upper end the area is given as

$A_1 = \pi r_1^2$

$A_1 = \pi(0.02)^2 = 1.26 \times 10^{-3} cm^2$

Also at the other end

$A_2 = \pi r_2^2$

$A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2$

now the speed at two ends is given as

$v_1 = \frac{20}{1.26 \times 10^{-3}}$

$v_1 = 159.15 m/s$

$v_2 = \frac{20}{0.314 \times 10^{-3}}$

$v_2 = 637 m/s$

now by Bernoulli's theorem we have

$P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2$

now we have

$0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0$

Now we have

$P_2 = -1.9 \times 10^8 Pa$

4 0

3 years ago

Which method is responsible for the transfer of heat in the atmosphere ?

k0ka [10]

Answer:

Explanation: Because conduction is when an object touches another object and convection happens with boiling water or the water cycle, the particles/water fall and rise.

4 0

3 years ago