Question

An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.2 m/s. A child on a bridge, 63 m above the river, sees the raft in the river below and attempts to drop a small stone onto the raft. The child releases the stone from rest. In order for the stone to hit the raft, what must be the horizontal distance between the raft and the bridge when the child releases the stone?

Answer 1

Answer:18.64 m

Explanation:

Given

speed of raft=5.2 m/s

height of bridge=63 m

let the distance between the raft and bridge be x

t = time taken by stone to reach at bottom

$x=5.2\times t$

$h=ut+\frac{at^2}{2}$

$63=0+\frac{9.8t^2}{2}$

$t^2=12.857$

t=3.58 s

$x=5.2\times 3.58=18.64 m$