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3 years ago

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In order of decreasing light-transmitting capabilities of materials, which is the correct sequence? A. Transparent -> translu

cent -> opaque B. Opaque -> transparent -> translucent C. Opaque -> translucent -> transparent D. Translucent -> transparent -> opaque

2 answers:

LenaWriter [7]3 years ago

6 0

transparent --> translucent --> opaque

A. Is the correct answer

AURORKA [14]3 years ago

3 0

Answer:

A is the correct answer :)))

Explanation:

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Four electrons and one proton are at rest, all at an approximate infiitne distance away from each other. This original arrangmen

murzikaleks [220]

Answer:

a) W = 1.63 10⁻²⁸ J, b) W = 1.407 10⁻²⁷ J, c) W = 1.68 10⁻²⁸ J,

d) W = - 4.93 10⁻²⁸ J

Explanation:

a) In this problem we have an electron at the origin, work is requested to carry another electron from infinity to the point x₂ = 0, y₂ = 2.00m

If we use the law of conservation of energy, work is the change in energy of the system

W = ΔU = U_∞ -U

the potential energy for point charges is

U =k $\sum \frac{q_i q_j}{r_{ij} }$

in this case we only have two particles

U = k $\frac{q_1q_2}{r_{12} }$

the distance is

r₁₂ = $\sqrt{(x_2-x_1)^2 + ( y_2-y_1)^2 }$

r₁₂ = $\sqrt{ 0 + ( 2-0)^2}$ Ra 0 + (2-0)

r₁₂ = √2= 1.4142 m

we substitute

W = k \sum \frac{q_i q_j}{r_{ij} }

let's calculate

W = $\frac{ 9 \ 10^9 (1.6 \ 10^{-19})^2 }{1.4142}$ 9 109 1.6 10-19 1.6 10-19 / 1.4142

W = 1.63 10⁻²⁸ J

b) the two electrons are fixed, what is the work to bring another electron to x₃ = 3.00 m y₃ = 0

in this case we have two fixed electrons

U = k $( \frac{q_1q_3}{r_{13} } + \frac{q_2q_3}{r_{23} } )$

in this case all charges are electrons

q₁ = q₂ = q₃ = q

W = U = k q² $( \frac{1}{r_{13} } + \frac{1}{r_{23} } )$

the distances are

r₁₃ = $\sqrt{(3-0)^2 + 0}$ RA (3.00 -0) 2 + 0

r₁₃ = 3

r₂₃ = $\sqrt{ 3^2 + 2^2}$ Ra (3 0) 2 + (2 0) 2

r₂₃ = √13

r₂₃ = 3.606 m

let's look for the job

W = U

let's calculate

W = ${9 \ 10^3 ( 1.6 10^{-19})^2 }({\frac{1}{3} + \frac{1}{3.606} } )$

W = 1.407 10⁻²⁷ J

c) the three electrons are fixed, we bring the four electron to x₄ = 3.00m,

y₄ = 4.00 m

W = U = k $( \frac{q_1q_4}{r_{14 }} + \frac{q_2q_4}{r_{24} } + \frac{q_3q_4}{r_{34} } )$

all charges are equal q₁ = q₂ = q₃ = q₄ = q

W = k q² $(\frac{1}{r_{14} } + \frac{1}{r_{24} } + \frac{1}{r_{34} } )$

let's look for the distances

r₁₄ = $\sqrt{3^2 +4^2}$

r₁₄ = 5 m

r₂₄ = $\sqrt{3^2 + ( 4-2)^2}$

r₂₄ = √13 = 3.606 m

r₃₄ = $\sqrt{(3-3)^2 + (4-0)^2}$

r₃₄ = 4 m

we calculate

W = 9 10⁹ (1.6 10⁻¹⁹)² $( \frac{1}{5} + \frac{1}{3.606} + \frac{1}{4} )$

W = 1.68 10⁻²⁸ J

d) we take the proton to the location x5 = 1m y5 = 1m

W = U = k $( \frac{q_1q_5}{r_{15} } + \frac{q_2q_5}{r_{25} } + \frac{q_3q_5}{r_{35} } + \frac{q_4q_5}{r_{45} } )$

in this case the charges have the same values but charge 5 is positive and the others negative, so the products of the charges give a negative value

W = - k q² $( \frac{1}{r_{15} } + \frac{1}{r_{25} } + \frac{1}{r_{35} } + \frac{1}{r_{45} } )$

we look for distances

r₁₅ = $\sqrt{ 1^2 +1^2}$ Ra (1-0) 2 + (1-0) 2

r₁₅ = √ 2 = 1.4142 m

r₂₅ = $\sqrt{ (2-1)^2 +1^2}$

r₂₅ = √2 = 1.4142 m

r₃₅ = $\sqrt{ ( 3-1)^2 +1^2}$

r₃₅ = √5 = 2.236 m

r₄₅ = $\sqrt{ (3-1)^2 + (4-1)^2}$

r₄₅ = √13 = 3.606 m

we calculate

W = - 9 10⁹ (1.6 10⁻¹⁹)² $( \frac{1}{1.4142} +\frac{1}{1.4142} + \frac{1}{2.236} + \frac{1}{3.606} )$

W = - 4.93 10⁻²⁸ J

3 0

3 years ago

A 25-ohm resistor at steady state draws a current of 10.8 amperes. its temperature is 310 k; the temperature of the surroundings

MA_775_DIABLO [31]

The total rate of entropy generation is 0.268 J/K.

Entropy, the degree of a gadget's thermal electricity consistent with unit temperature that is unavailable for doing useful paintings. due to the fact work is acquired from ordered molecular motion, the quantity of entropy is likewise a measure of the molecular sickness, or randomness, of a machine.

Resistance of resistor R = 25 ohm

the total rate of entropy generation ?

Current flowing through resistor I = 10 A

Heat generation due to resistance , Q = I2R = 100*25 = 2500 J

Resistor temperature T = 310 K

Surrounding temperature Ts = 300 K

Entropy change for Resistor, heat lost due to the resistance to the surrounding then Q = -ve

(ΔS)syst = - Q/T = - 2500 J/310K = - 8.064 J/K

Entropy change for the system: here heat gain from the resistor, Q = +ve

(ΔS)surr = +Q/Ts = 2500J/300K = 8.333 J/K

Total Entropy generation :

(ΔS)tot = (ΔS)syst + (ΔS) Surr = -8.064 + 8.333 = 0.268 J/K

Learn more about entropy here:- brainly.com/question/6364271

#SPJ4

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2 years ago

Which of the following would be an example of basic research?

lara [203]

Answer: Experimenting to determine the fundamental properties of x-rays.

Explanation:

Scientific basic research aims to find the fundaments or principles of the phenomena.

The basic research is intended to understand the matter, its nature, its properties, its behavior. It searches to make theory. To finding how the things work but not how to use those things for a determined purpose.

The study of the properties of the atom to understand what it is, how it interacts with other atoms, how it determines the properties of the matter are some examples of basic research, such as experimenting to determine the fundamental properties of x-rays is.

On the other hand, the other examples given, Spencer's research on WWII radar technology that led to the invention of the microwave oven, Edison's research and use of other scientists' work to invent the light bulb, and Morrison and Franscioni's research done to create the Frisbee, are examples of applied research science. This is research to find a valuable use of some scientific knowledge.

6 0

4 years ago

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When we see a meteor shower, it means that ________.

Irina18 [472]

Answer:

option A

Explanation:

The meteor shower is the celestial activity in which meteors are observed to radiate or originate from one point.

Meteors are nothing but dust or ice from the trails of comets. Most of the meteors are less than the size of the sand particle.

We will see comet shower when we earth will cross the orbit of the comet.

Hence, the correct answer is option A

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4 years ago

The ability of a muscle to force against a resistance one time.

Ksenya-84 [330]

6 -B
7-D
8-D
9-D
11-A
12-A
13-B
14-D
15-A

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3 years ago

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