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anygoal [31]
3 years ago
11

A population of birds walks along the shores of a swampy area eating small crabs. Climatic changes cause the water level in the

area to increase. Which genetic variation in the bird population will be at an advantance leading to greater survival in the area?
Physics
1 answer:
sergejj [24]3 years ago
4 0

R there any answer choices

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A vector has components Ax = 12.0 m and Ay= 5.00 m. What is the angle that vector A makes with the x-axis?a. 67.4ob. 32.6oc. 22.
antoniya [11.8K]

Answer:

C.22.6°

Explanation:

Ax = ACosθ,

A = Ax/Cosθ    .....equ1

Ay = Asinθ,

A= Ay/sinθ      .....equ 2

equate equation 1 and 2.

Ax/Cosθ = Ay/sinθ

Ax = 12.0 m,  Ay= 5.00 m

12/Cosθ = 5/sinθ

θ = 22.6°

5 0
3 years ago
How does temperature influence the appearance of a star? Give an example in your response.
loris [4]

The cooler the temp of the star the star would appear to glisten a red. if the star is warmer the star would be a light blue or blue. An example would be the tiny red dwarf stars. they only have 7% of the suns heat so they appear red.

5 0
3 years ago
A roller coaster car is going over the top of a 15-m-radius circular rise. The passenger in the roller coaster has a true weight
konstantin123 [22]

Answer:

v = 7.67 m/s

Explanation:

The equation for apparent weight in the situation of weightlessness is given as:

Apparent Weight = m(g - a)

where,

Apparent Weight = 360 N

m = mass passenger = 61.2 kg

a = acceleration of roller coaster

g = acceleration due to gravity = 9.8 m/s²

Therefore,

360 N = (61.2 kg)(9.8 m/s² - a)

9.8 m/s² - a = 360 N/61.2 kg

a = 9.8 m/s² - 5.88 m/s²

a = 3.92 m/s²

Since, this acceleration is due to the change in direction of velocity on a circular path. Therefore, it can b represented by centripetal acceleration and its formula is given as:

a = v²/r

where,

a = centripetal acceleration = 3.92 m/s²

v = speed of roller coaster = ?

r = radius of circular rise = 15 m

Therefore,

3.92 m/s² = v²/15 m

v² = (3.92 m.s²)(15 m)

v = √(58.8 m²/s²)

<u>v = 7.67 m/s</u>

7 0
3 years ago
A car passes point “A” and then 120 meters later. It’s velocity was measured 21 m/s. If it’s acceleration was constant at 0.853
Norma-Jean [14]

Recall that

{v_f}^2-{v_i}^2=2a\Delta x

where v_i and v_f are the initial and final velocities, respecitvely; a is the acceleration; and \Delta x is the change in position.

So we have

\left(21\dfrac{\rm m}{\rm s}\right)^2-{v_i}^2=2\left(0.853\dfrac{\rm m}{\mathrm s^2}\right)(120\,\mathrm m)

\implies v_i\approx\boxed{15.4\dfrac{\rm m}{\rm s}}

(Normally, this equation has two solutions, but we omit the negative one because the car is moving in one direction.)

7 0
2 years ago
PLEASE HELP ME IM TIMED
Novosadov [1.4K]
Yeah it’s the mantle
6 0
3 years ago
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