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beks73 [17]
3 years ago
14

If there is an attractive force between all objects, why do we not feel ourselves gravitating toward massive buildings in our vi

cinity?
Physics
2 answers:
mars1129 [50]3 years ago
8 0
The mass of an object affects how powerful the attractive force is. To feel the pull / gravitation the mass of the object would have to be huge, bigger than that of massive buildings
HACTEHA [7]3 years ago
4 0
Because there is a far more massive nearby object that's attracting you to it. That object is the planet you're standing on. Compared to its mass, that massive building could just as well be a speck of dust or a clump of lint. The gravitational attraction toward Earth completely swamps out the attraction toward anything else.
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gayaneshka [121]
This is confusing yes
3 0
3 years ago
A 50.0 kg driver is riding at 35.0 m/s in her red sports car when she must suddenly slam on the brakes to avoid
egoroff_w [7]

Answer:

3500N

Explanation:

Given parameters:

Mass of driver  = 50kg

Speed  = 35m/s

Time  = 0.5s

Unknown:

Average force the seat belt exerts on her = ?

Solution:

The average force the seat belt exerts on her can be deduced from Newton's second law of motion.

   F = mass x acceleration

So;

     F  = mass x  \frac{change in velocity }{time}

  F  = 50 x \frac{35}{0.5}    = 3500N

8 0
3 years ago
A 0.500-kg block, starting at rest, slides down a 30.0° incline with static and kinetic friction coefficients of 0.350 and 0.250
Leviafan [203]

Answer:x=23.4 cm

Explanation:

Given

mass of block m=0.5 kg

inclination \theta =30

coefficient of static friction \mu =0.35

coefficient of kinetic friction \mu _k=0.25

distance traveled d=77.3 cm

spring constant k=35 N/m

work done by gravity+work done by friction=Energy stored in Spring

mg\sin \theta d-\mu _kmg\cos \theta d=\frac{kx^2}{2}

mgd\left ( \sin \theta -\mu _k\cos \theta \right )=\frac{kx^2}{2}

0.5\times 9.8\times 0.773\left ( \sin 30-0.25\cos 30\right )=\frac{35\times x^2}{2}

x=\sqrt{\frac{2\times 0.5\times 9.8\times 0.773(\sin 30-0.25\times \cos 30)}{35}}

x=0.234 m

x=23.4 cm

6 0
3 years ago
Two identical positive charges exert a repulsive force of 6.1 × 10−9 n when separated by a distance 3.6 × 10−10 m. calculate the
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A horse pulls a plow with a 242 N force for
prohojiy [21]

Answer: The answer is D

Explanation: i had the same question and i just guessed and got it first try

4 0
3 years ago
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