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beks73 [17]
4 years ago
14

If there is an attractive force between all objects, why do we not feel ourselves gravitating toward massive buildings in our vi

cinity?
Physics
2 answers:
mars1129 [50]4 years ago
8 0
The mass of an object affects how powerful the attractive force is. To feel the pull / gravitation the mass of the object would have to be huge, bigger than that of massive buildings
HACTEHA [7]4 years ago
4 0
Because there is a far more massive nearby object that's attracting you to it. That object is the planet you're standing on. Compared to its mass, that massive building could just as well be a speck of dust or a clump of lint. The gravitational attraction toward Earth completely swamps out the attraction toward anything else.
You might be interested in
Phase Changes
worty [1.4K]

Answer:

The answer to your question below

Explanation:

Processes from solid to liquid or from liquid to gas absorb energy.

Processes from gas to liquid or liquid to solid release energy.

Condensation      phase change that releases heat

Freezing                phase change that releases heat

Melting                  phase change that absorbs heat

Sublimation          phase change that absorbs heat  

Vaporization         phase change that absorbs heat

7 0
3 years ago
If an object is dropped from a tall building and hits the ground 3.0 s. later, what is the magnitude of the object's displacemen
marin [14]

Find the velocity of the object after one second.  

v = vo + at  

v = (0 m/s) + (9.8 m/s^2)(1 s)  

v = 9.8 m/s  

Now, using that, you can find the displacement in that one second between 1 and 2.  

d = vot + (1/2)at^2  

d = (9.8 m/s)(1 s) + (1/2)(9.8 m/s^2)(1 s)^2  

d = 14.7 m  


5 0
3 years ago
Read 2 more answers
A box is on a sloped ramp. The angle of incline of the ramp is 34
Paul [167]

Explanation:

parallel force component = mg sin (angle in degree)

=58 sin 34*

=32.433N

4 0
3 years ago
A shark swims around his circular pool. What is the centripetal force of the 681kg shark if the pool has a diameter of 14m and i
blsea [12.9K]
<span>29 Newtons
   Centripetal force is modeled by the equation:
  F = MV^2/R where
 F = force
 M = Mass
 V = Velocity
 R = Radius

   I will assume the shark is swimming in a circle with a radius of 14 m / 2 = 7 m. The actual radius will be smaller, but I'll assume that the question is simply poorly worded. So we need to calculate the velocity of the shark. The circumference of the circle is pi*14m = 43.98229715 m. And since velocity is defined as distance over time, we have a velocity of 43.98229715 m / 80 s = 0.549778714 m/s.

   Now substitute the known values into the equation for centripetal force.
 F = MV^2/R
 F = 681 kg * ( 0.549778714 m/s)^2 / 7m
 F = 681 kg * 0.302256635 m^2/s^2 / 7m
 F = 205.8367683 kg*m^2/s^2 / 7m
 F = 29.40525261 kg*m/s^2
 F = 29.40525261 N
   Rounding to 2 significant figures gives a force of 29 Newtons.</span>
5 0
3 years ago
PLEASE HELP ASAPPPPP​
leva [86]

Answer:

link

Explanation:

ww.comhwhelp

4 0
3 years ago
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