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zalisa [80]
3 years ago
12

When two waves interact with their crests and troughs in alignment is called?

Physics
2 answers:
marissa [1.9K]3 years ago
5 0

When two waves interact with their crests and troughs in alignment is called constructive interference. If two waves of the same wavelength occupy the same space in such a way that their crests and troughs align, the wave they produce will have an amplitude greater than that possessed by either wave initially. This is known as constructive interference. The more closely the waves are in phase—that is, perfectly aligned—the more constructive the interference.

lapo4ka [179]3 years ago
3 0

Answer:

Constructive interference.

Explanation:

Constructive interference is the interference which  occurs when the peak of the two waves add together and the condition is that these two waves are in same phase, so that the resulting wave amplitude  is equal to the addition of the individual amplitudes.

Crest is the highest point of the wave. Trough is defined as the lowest amplitude of the wave. The occurrence of constructive interference will occurs  when the peaks of the  two waves meet and overlap which is called the alignment of crest and trough.

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3 years ago
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ArbitrLikvidat [17]

Answer:

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3 years ago
What must be true of a force that causes an object to move in a circular motion?
AlladinOne [14]

Before going to answer this question, first we have to understand centripetal force.

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7 0
3 years ago
Read 2 more answers
Assume the radius of an atom, which can be represented as a hard sphere, is r = 1.95 Å. The atom is placed in a (a) simple cubic
Nuetrik [128]

Answer:

(a) A = 3.90 \AA

(b) A = 4.50 \AA

(c) A = 5.51 \AA

(d) A = 9.02 \AA

Solution:

As per the question:

Radius of atom, r = 1.95 \AA = 1.95\times 10^{- 10} m

Now,

(a) For a simple cubic lattice, lattice constant A:

A = 2r

A = 2\times 1.95 = 3.90 \AA

(b) For body centered cubic lattice:

A = \frac{4}{\sqrt{3}}r

A = \frac{4}{\sqrt{3}}\times 1.95 = 4.50 \AA

(c) For face centered cubic lattice:

A = 2{\sqrt{2}}r

A = 2{\sqrt{2}}\times 1.95 = 5.51 \AA

(d) For diamond lattice:

A = 2\times \frac{4}{\sqrt{3}}r

A = 2\times \frac{4}{\sqrt{3}}\times 1.95 = 9.02 \AA

6 0
3 years ago
Calculate the minimum amount of energy, in joules, required to completely melt 145 g of silver initially at 22.0°C. The melting
Tcecarenko [31]

Answer:

47391.8 J

Explanation:

Q = m c Δt

For melting, Δt = (962-22)°C

Heat required to attain melting point = 145 x 10 ⁻³ x 236 x 940 =

= 32166.8 J

Heat required to melt at melting point = m L , L is latent heat of fusion.

= 145 x 10⁻³ x 105 x 10³ = 15225 J

Total energy required = 47391.8 J

6 0
4 years ago
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