If the weight of the metal disk is 1.0 N, the normal force acting on the metal disk is also 1.0 N but acting in the opposite direction.
<h3>What is the normal force?</h3>
According to Newton Law, action and reaction are equal and opposite. The reaction force is equal in magnitude to the weight of an object but opposite in direction.
Having said that, if the weight of the metal disk is 1.0 N, the normal force acting on the metal disk is also 1.0 N but acting in the opposite direction.
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The correct answer is:
<span>A. orbiting closer to the earths surface.
In fact, the gravitational force exerted by the Earth on the satellite is
</span>

<span>where
G is the gravitational constant
M is the Earth mass
m is the satellite mass
r is the distance of the satellite from the Earth's surface
We can see that, if the satellite orbits closer to the Earth's surface, its distance r from the centre of the planet decreases. But when r decreases, F (the gravitational force) increases, so A is the correct answer.</span>
Answer:
a) 24.43 radians per second
b) 268.73 inches per second
Explanation:
a) The angular speed of the fan on Celsius degrees/second is 1400, so we should convert that value to radians using the fact that 2π rad = 360 °C:


b) Linear speed on a point of the blade is related with angular speed of the fan by the equation

with v linear speed, ω angular speed and r the radius of the blades. So:

Radians isn't really a unity; it is dimensionless so we can put it or not. So:

Answer:
Work done, W = 1786.17J
Explanation:
The question says "A 75.0-kg painter climbs a 2.75-m ladder that is leaning against a vertical wall. The ladder makes an angle of 30.0 ° with the wall. How much work (in Joules) does gravity do on the painter? "
Mass of a painter, m = 75 kg
He climbs 2.75-m ladder that is leaning against a vertical wall.
The ladder makes an angle of 30 degrees with the wall.
We need to find the work done by the gravity on the painter.
The angle between the weight of the painter and the displacement is :
θ = 180 - 30
= 150°
The work done by the gravity is given by :

Hence, the required work done is 1786.17 J.