Incomplete question.The complete question is
A tall cylinder contains 20 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until the total liquid depth is 40 cm. What is the gauge pressure at the bottom of the cylinder? Suppose that the density of oil is 900 kg/m3.
Answer:
Total gauge pressure= 3724Pa or 3.724kPa
Explanation:
Pressure (water alone) = (1,000 x 9.8 x 0.2m) = 1,960Pa.
Pressure (oil on top) = (900 x9.8 x 0.2m) = 1,764Pa.
Total gauge pressure at bottom = (1,960 + 1,764) = 3724Pa or 3.724kPa
Answer:
where F is the friction force that is the same for both boxes
Explanation:
So the same boxes at the same mass m would create a same friction force, let this force be F. The net force in the first and 2nd cases would be
- 1st case: F1 - F
- 2nd case F2 - F
According to Newton 2nd law, this net would make acceleration
- 1st case 
- 2nd case
Since 
Do you have the options? I would say swerve?
Answer:
I believe the answer is triangle
Hope it helps!
