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velikii [3]
3 years ago
9

Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and

Physics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:

1.08x10⁻⁷

Explanation:

F=(GM₁M₂)/r²

=((6.67x10⁻¹¹)(70)(52))/(1.5²)

=2.42788x10⁻⁷/2.25

=1.07905778x10⁻⁷

≈1.08x10⁻⁷

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The answer is that FRICTION PRODUCES HEAT.
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Dimension for electric charge
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Answer:

AT

Explanation:

Dimensions of current = A

Dimensions of time = T

Current = Charge / time

Therefore Charge = Current × time

                 [Charge] = [Current] × [time]

                                 = AT            

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Please help? physics question...
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3 years ago
A certain superconducting magnet in the form of a solenoid of length 0.24 m can generate a magnetic field of 7.0 T in its core w
tatiyna

Answer:

N=14854.5turns

Explanation:

Given data

Length L=0.24 m

Magnetic field B=7.0 T

Current I=90 A

To find

Number of turns N

Solution

As we know that magnetic field is given as:

B=u_{o}I\frac{N}{L}

Rearrange the equation and solve for N

So

B=u_{o}I\frac{N}{L}\\\frac{B}{u_{o}I} =\frac{N}{L} \\N=\frac{LB}{u_{o}I}\\N=\frac{(0.24m)(7.0T)}{4\pi *10^{-7}*(90A)} \\N=14854.5turns

5 0
3 years ago
What is the net displacement of the particle between 0 seconds and 80seconds?
Ira Lisetskai [31]

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = \frac{1}{2}(\text{Base})(\text{height})

                                   = \frac{1}{2}(40)(4)

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Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = \frac{1}{2}(40)(4)

                        = 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.

7 0
3 years ago
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