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Eddi Din [679]
3 years ago
13

I need help!!!! Someone help please

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

Rewrite using the commutative property of multiplication.

− 4 t s

Step-by-step explanation:

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What is the range of the following set? 48, 47, 54, 55, 52, 48, 46, 53, 45
umka2103 [35]

Answer:

10

Step-by-step explanation:

the range is the difference between the biggest and the smallest number

55-45=10

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3 years ago
What’s 80 percent in fractions
Greeley [361]
The answer to that is 80 percent as a fraction is 8/10
4 0
3 years ago
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What’s is the answer
kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

(x^{2} )^{3} = x^6

(x^{3} )^5=x^{15}


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

(x^{2} )(x^{3})=x^{5}

(x^{1} )(x^{2})=x^{3}


(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}

You multiply 3 into each exponent in the numerator and the denominator

\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}


When you have something like this:

\frac{x^{2}}{x^5}

You subtract the exponents together, so:

\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}


Your answer is the second option

3 0
3 years ago
Please help me out with this question ❤️ thank youu
stepan [7]

Answer:

5^6=15625

Step-by-step explanation: the little thing on the right of log to the power of the left of = is equal to the big numbers right of log

6 0
3 years ago
James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described?
nignag [31]
32 is your initial value, because that is what he starts with

6 0
3 years ago
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