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babymother [125]
3 years ago
5

sam gets 15 vacation days each year. By june 1st, sam had used 6 of his vacation days. what fraction on the year's total did he

use so far?
Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Answer:

Step-by-step explanation: put your fraction 6 over 15

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A merchant bought some shirts for $120. The next day the price charged for each shirt was reduced by $1. The merchant calculated
Goshia [24]

Answer:

The merchant buys 30 shirts originally.

Step-by-step explanation:

Let us assume that the merchant bought x numbers of shirts in $120.

So, the cost for each shirt is $\frac{120}{x}.

Now, if the cost for each shirt is reduced by 1$, then he would have bought 10 shirts more i.e. (x + 10) shirts in $120.

So, we can write the following equation as  

(\frac{120}{x} - 1)(x + 10) = 120

⇒(120 - x)(x + 10) = 120x

⇒ 120x - 10x + 1200 - x² = 120x

⇒ x² +10x - 1200 = 0

⇒ x² + 40x - 30x - 1200 = 0

⇒(x + 40)(x - 30) = 0

⇒ x = - 40 or x = 30

But x can not be negative.

Hence, the merchant buys 30 shirts originally. (Answer)

6 0
3 years ago
Solve for all values of c in simplest form.<br> |C – 21 |= 12
Rina8888 [55]

Answer:

33, 9

Step-by-step explanation:

I33-21I=12

I9-21I=

I-12I=12

Every SUM of an absolute value will always be positive!!

5 0
3 years ago
An art club is going to a museum. Six adults are going. 18 more kids than adults are going. Adults tickets cost $24 each, which
dybincka [34]

so their are 6 adults and 24 kids because when you add 18+6  and get 24

then you multiply 6(24) because adult tickets are 24 and get 144

then you multiply 24(12) because student tickets are half as much as parents so they are 12 and you multiply by 24 kids and get 288

then you add 288 student tickets total price +144 adult ticket total price =432 total cost fro all tickets

8 0
3 years ago
What are the measurements of the bases and the area of the trapezoid?
Luda [366]
The bases of the trapezoid are 24 m and 9.6 m.

The area of the trapezoid is 141.12 m².
7 0
3 years ago
What is the solution to the pair of simultaneous equations? 2x+y=5. 3x-2y=4​
densk [106]

Answer:

(2, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Distributive Property

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

2x + y = 5

3x - 2y = 4

<u>Step 2: Rewrite Systems</u>

<em>Manipulate 1st equation</em>

  1. [Subtraction Property of Equality] Subtract 2x on both sides:                      y = 5 - 2x

<u>Step 3: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em> [2nd Equation]:                                                                         3x - 2(5 - 2x) = 4
  2. [Distributive Property] Distribute -2:                                                                3x - 10 + 4x = 4
  3. [Addition] Combine like terms:                                                                        7x - 10 = 4
  4. [Addition Property of Equality] Add 10 on both sides:                                   7x = 14
  5. [Division Property of Equality] Divide 7 on both sides:                                 x = 2

<u>Step 4: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em> [Modified 1st Equation]:                                                           y = 5 - 2(2)
  2. Multiply:                                                                                                             y = 5 - 4
  3. Subtract:                                                                                                            y = 1
3 0
3 years ago
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