given triangle ABC with sides AB=3x+4, BC=2x+5, AC=4x, determine the values of X such that triangle ABC exists.

1 answer:

5 0

You can a teacher lol

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ollegr [7]

$y = \frac{x - 5}{x^{2} - 6x + 5}$
$y = \frac{x - 5}{(x - 1)(x - 5)}$
$y = \frac{1}{x - 1}$

x - 1 = 0
+ 1 + 1
x = 1

3 0

3 years ago

maxonik [38]

To do this, use this formula=The area is always pie times the radius to the 2nd. But this is for a semicircle so divdie your answer by 2

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3 years ago

jekas [21]

58 I just took the test and got it right

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2 years ago

prisoha [69]

Answer:

Your answer is RSP. THE 3RD one

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3 years ago

kvasek [131]

.16x=12 x= 12/.16. x=75

8 0

3 years ago