Answer:
q = 15
Step-by-step explanation:
Given
f(x) = x² + px + q , then
f(3) = 3² + 3p + q = 6 , that is
9 + 3p + q = 6 ( subtract 9 from both sides )
3p + q = - 3 → (1)
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f'(x) = 2x + p , then
f'(3) = 2(3) + p = 0, that is
6 + p = 0 ( subtract 6 from both sides )
p = - 6
Substitute p = - 6 into (1)
3(- 6) + q = - 3
- 18 + q = - 3 ( add 18 to both sides )
q = 15
Answer:
54
Step-by-step explanation:
multiply by 1.8 and add 32
12*1.8=21.6
21.6+32=53.6
53.6 rounded = 54
Answer: m∠BCE = 63°
m∠BAD = 76°
Step-by-step explanation:
Problem 1:
Given
m∠BEC = 90°
m∠EBC = 27°
Total = 117°
Solution:
Subtract 180° - 117° = m∠BCE = 63°
Problem 2:
Given
m∠ADE = 52°
m∠ABE = 52°
Total = 104°
Solution:
Subtract 180° - 104° = m∠BAD = 76°
Answer:
1519
Step-by-step explanation:
if wrong super sooryyyyy :(
Answer: D
Step-by-step explanation: By using SOH for sin A, 'S' being sin, 'O' being opposite side of angle A and 'H' being the hypotenuse which is the longest part of the triangle you would find that 15 is opposite from Sin A and 17 the hypotenuse, 15/17.
For cos A you would use CAH, C= cos, A which is the adjacent of the triangle located next to angel A which is 8, and H= hypotenuse (also note that the hypotenuse never changes even if the angle may be different) CAH would be cos A = 8/17
