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Ostrovityanka [42]

3 years ago

11

A shift register is a synchronous sequential circuit that will store or move data. It consists of several flip-flops, which are

connected so that data are transferred into and out of the flip-flops in a standard pattern.

1 answer:

GrogVix [38]3 years ago

8 0

Answer:

yeahHhhhhhhhhh

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Economics is the study of how individuals and societies make choices under the condition of

k0ka [10]

Answer:

ig scarcity

Explanation:

Hope it Helps!!!

3 0

2 years ago

Both portions of the rod ABC are made of an aluminum for whichE = 70 GPa. Knowing that the magnitude of P is 4 kN, determine(a)

san4es73 [151]

Explanation:

Δ $L_{BC}$ = Δ $L_{AB}$

$\frac{(Q - 4000)(0.5)}{3.14* 0.03 *0.03 *70*10^{9} }$ (1)

= $\frac{4000*0.4}{3.14*0.01*0.01*70*10^{9} }$

Q = 32,800 N

now put this value in equation 1.

Deflection of B = $\frac{(32800-4000)(0.5)}{3.14*0.03*0.03*70*10^{9} }$

= 0.0728 mm

4 0

4 years ago

Using the AASHTO 1993 Flexible Pavement Design Procedure, design a pavement cross section that will provide 10 years service. Th

natali 33 [55]

Answer:

Check the explanation

Explanation:

Single Unit Truck ESAL = 43.38 + 5.16 = 48.54

Semi Unit Truck ESAL = 43.38+ 6.00+7.4 = 56.78

So total ESAL's during design life = (400*48.54 + 350*56.78)*365*10/18000 = (19416+19873)*3650= 3939

Kindly check the attached image

Here

Reliability = 95% = 0.95, therefore ZR = -1.645, S0 = 0.4, MR = 18

Delta PSI = 4.2-2.5= 1.7

Resilient Modulus = 18000 psi, So MR = 18

Assume SN = 3.0 for flexible pavements

There W18 calculates to 0.26807

So

log10 (3939) = 9.36*log10(SN+1) -.2/(.4+1094/(SN+1)5.19)) -6.01

Structural Number SN = a1*d1 + a2*d2 *m2 +a2*d3 *m3

= a1*d1 + a2*d2 +a2*d3

5 0

3 years ago

How do you know which forces works for free bodies

miss Akunina [59]

Answer:

Gravitational force (pulled downward by the Earth)

Normal force (pushed upward by the ground)

Applied force (pushed by the person)

Friction force (pulled opposite the direction of motion by the roughness of the ground)

5 0

3 years ago

Find the percent change in cutting speed required to give an 80% reduction in tool life when the value of n is 0.12.

vaieri [72.5K]

Answer:21.3%

Explanation:

Given

80 % reduction in tool life

According to Taylor's tool life

$VT^n$ =c

where V is cutting velocity

T=tool life of tool

80 % tool life reduction i.e. New tool Life is 0.2T

Thus

$VT^{0.12}=V'\left ( 0.2T\right )^{0.12}$

$V'=\frac{V}{0.2^{0.12}}$

$V'=\frac{V}{0.824}$ =1.213V

Thus a change of 21.3 %(increment) is required to reduce tool life by 80%

6 0

3 years ago