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Elden [556K]
4 years ago
5

Define the isentropic efficiency for each of the following 3. a. i. Adiabatic turbine ii. Adiabatic compressor iii. Adiabatic no

zzle
Engineering
1 answer:
Pavlova-9 [17]4 years ago
3 0

Answer:

a)\eta_{st}=\dfrac{\Delta h_{actual}}{\Delta _{ideal}}

b)\eta_{sc}=\dfrac{\Delta h_{ideal}}{\Delta _{actual}}

c)\eta_{sn}=\dfrac{\Delta h_{actual}}{\Delta _{ideal}}

Explanation:

a)

Adiabatic turbine

Adiabatic turbine means turbine can not reject or take heat from surrounding.

Isentropic efficiency of turbine can be define as the ratio of actual work out put to the Ideal or isentropic work out put.Ideal means when turbine will give maximum work and there is no any friction losses we can say when process is isentropic.

Isentropic efficiency of turbine=(Actual work output)/(Ideal work output)

\eta_{st}=\dfrac{\Delta h_{actual}}{\Delta _{ideal}}

b)

Adiabatic compressor

Isentropic efficiency of compressor can be define as the ratio of ideal or isentropic work in put to the actual work  in put.

Isentropic efficiency of turbine=(Ideal work input)/(actual work input)

\eta_{sc}=\dfrac{\Delta h_{ideal}}{\Delta _{actual}}

c)Adiabatic nozzle

We know that nozzle is device which used to accelerate the fluid.

Basically it covert pressure energy to kinetic energy.

Isentropic efficiency of nozzle can be define as the ratio of actual enthalpy drop put to the Ideal or isentropic enthalpy drop.

\eta_{sn}=\dfrac{\Delta h_{actual}}{\Delta _{ideal}}

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Given: A graphite-moderated nuclear reactor. Heat is generated uniformly in uranium rods of 0.05m diameter at the rate of 7.5 x
sineoko [7]

Answer:

The maximum temperature at the center of the rod is found to be 517.24 °C

Explanation:

Assumptions:

1- Heat transfer is steady.

2- Heat transfer is in one dimension, due to axial symmetry.

3- Heat generation is uniform.

Now, we consider an inner imaginary cylinder of radius R inside the actual uranium rod of radius Ro. So, from steady state conditions, we know that, heat generated within the rod will be equal to the heat conducted at any point of the rod. So, from Fourier's Law, we write:

Heat Conduction Through Rod = Heat Generation

-kAdT/dr = qV

where,

k = thermal conductivity = 29.5 W/m.K

q = heat generation per unit volume = 7.5 x 10^7 W/m³

V = volume of rod = π r² l

A = area of rod = 2π r l

using these values, we get:

dT = - (q/2k)(r dr)

integrating from r = 0, where T(0) = To = Maximum center temperature, to r = Ro, where, T(Ro) = Ts = surface temperature = 120°C.

To -Ts = qr²/4k

To = Ts + qr²/4k

To = 120°C + (7.5 x 10^7 W/m³)(0.025 m)²/(4)(29.5 W/m.°C)

To = 120° C + 397.24° C

<u>To = 517.24° C</u>

5 0
4 years ago
I need answer to this question
blagie [28]

Answer:

1. Graph C

2. Friction

Explanation:

1. The line on all of the graphs shown represents velocity. The formula for velocity is v=\frac{d}{t} where d is distance and t is time. Focusing on the first lap, the starting point on the graph should be the origin and the "ending" point should be (20, 3). These requirements eliminate graph A as an answer because its "end" is not (20, 3). During the break, the student does not move, so the slope of the line should be completely horizontal. The break lasted for 5 minutes, so the correct graph should have a horizontal line between the points (20, 3) and (25, 3). This requirement eliminates graph B and D because their break is either not long enough (B) or too long (D).

2. Friction slows down the movement of objects. When an object is rough, it produces more friction which causes the object to be slowed more. When an object is smooth, friction slows it less than it would for a rough object.

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3 years ago
Which of the following is the LEAST-Likely cause of tire wear? A) Underinflation B) Braking C) Acceleration D) Tire rotation
mihalych1998 [28]

Answer:

Tire rotation is the least likely cause of tire wear. So, the option D is correct.

Explanation:

Step1

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Step2

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Step3

Acceleration on the vehicle increases the rubbing action as well as the wear and tear on the tire. So, acceleration is an also a major cause of tire wear.

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Elevators makes it go up and down
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3 years ago
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kari74 [83]

Answer:

Pressure = 16\ pa

Explanation:

Given

Force = 4000N

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Required

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Pressure is calculated using:

Pressure = \frac{Force}{Area}

Substitute values for Force and Area

Pressure = \frac{4000N}{250m^2}

Pressure = 16N/m^2

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3 years ago
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