The answer is true. fluorescence demonstrates a sparkly like light beam and also can bounce off of other beams
Answer:
66.8°C
Explanation:
dQ = m*cp*dT where:
m = mass of block
cp = specific heat of iron
dT = temperature change
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dQ = 3.5 10^4 J
cp = 0.45 Kj / Kg = 450 J / Kg
3.5 10^4 = 2.3 * 450 * dt-----dt = 35000 / 450 * 2.3 = 33.8 °
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Final temperature = 33 + 33.8 = 66.8 °C
Its B- Ground, just took the test
Answer: 0.512 kgm²
Explanation:
Given
Force, F = 2*10^3 N
Angular acceleration, α = 121 rad/s²
Lever arm, r(⊥) = 3.1 cm = 3.1*10^-2 m
τ = r(⊥) * F
Also,
τ = Iα
Using the first equation, we have
τ = r(⊥) * F
τ = 0.031 * 2*10^3
τ = 62 Nm
Now we calculate for the inertia using the second equation
τ = Iα, making I subject of formula, we have
I = τ / α, on substituting, we have
I = 62 / 121
I = 0.512 kgm²
Thus, the moment of inertia of the boxers forearm is 0.512 kgm²
