If anyone can answer these that aren't done you'll get 30 points plus how many ever I give you just by myself but just for answe
ring those questions you get 30
1 answer:
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Answer:
a)
b)
c)
Step-by-step explanation:
The question is incomplete:
<em>(a) What is the probability that Celia is first in line? (b) What is the probability that Celia is first in line and Felicity is last in line? (c) What is the probability that Celia and Felicity are next to each other in the line?</em>
a) The probability that Celia is first in line, if there are n kids and all of them have the same chance, is 1/n.
b) The probability that Celia is first in line and Felicity is last in line is
.
It is deducted like that:
If Celia is placed in the first line (what has a probablity of 1/n), there are left (n-1) kids. Then, the probability of placing Felicity in the last place is 1/(n-1).
Both probabilities multiplied give 1/(n*(n-1)).
c) The probability that Celia and Felicity are next to each other in the line is
There are n! combinations for kids lines, where (n-1)! permutations have Celia before Felicity and other (n-1)! permutations have Felicity before Celia.
Then, we have 2(n-1)! permutations that have Celia and Felicity next to each other, over n! permutations possible.
Answer:
$28
Step-by-step explanation:
Given:
data = [22,30,35,25,25,20,27]
For eight night, the new list is:
new_data = [22,30,35,25,25,20,27,x]
Mean = 26.50
Mean Formula:
Therefore:
Multiply both sides by 8:
Solve for x:
Subtract 184 both sides:
Therefore, she will earn $28 in eighth night
The attachment below is the result of combining all eighth data as we get 26.5 through python language with numpy package.
