the large bag is 5/6 lb, the smaller bags will be 1/3 lb, so it should be 5/6 ÷ 1/3
![\bf \cfrac{5}{6}\div \cfrac{1}{3}\implies \cfrac{5}{\underset{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}\cdot \cfrac{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies \cfrac{5}{2}\implies 2\frac{1}{2}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7B5%7D%7B6%7D%5Cdiv%20%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B%5Cunderset%7B2%7D%7B~~%5Cbegin%7Bmatrix%7D%206%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7D%5Ccdot%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%203%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B1%7D%5Cimplies%20%5Ccfrac%7B5%7D%7B2%7D%5Cimplies%202%5Cfrac%7B1%7D%7B2%7D)
Answer:
0.589
Step-by-step explanation:
THis is a conditional probability question. Let's look at the formula first:
P (A | B) = P(A∩B)/P(B)
" | " means "given that".
So, it means, the <u><em>"Probabilty A given that B is equal to Probability A intersection B divided by probability of B."</em></u>
<u><em /></u>
So we want to know P (Female | Undergraduate ). This in formula is:
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
Now,
P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,
P (Female ∩ Undergraduate) = 0.43
Also,
P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73
<em>plugging into the formula we get:</em>
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
=0.43/0.73 = 0.589
this is the answer.
<span> |2x − 5| − 2 = 3
</span><span>1) |2x − 5| = 3 +2
2)</span><span> |2x − 5| = 5
3) 2x-5 = 5, or 2x-5= -5
4)2x=10, or 2x=0
5) x = 5 , or x = 0
Check:
</span> |2x − 5| − 2 = 3
|2*5− 5| − 2 = 3 or |2*0 − 5| − 2 = 3
|5|-2=3 or |-5| -2 =3
3=3 (true) or 3=3 (true)
All steps are correct.
Answer:
<em><u>1 and 5</u></em>
Step-by-step explanation:
The squares have a side length of 10 and 1 square side is the radius of the half-circles. Since there are two half-circles, find the circumference for one full circle:
Insert the radius:
Simplify pi:
Simplify multiplication:
The circumference of the circles is 62.8. Now find the perimeter of the exposed squares with side length 10. There are 4 exposed sides, which equals one square. Find the perimeter:
Add the perimeter of the circle and the square together:
Now see which of the options gives you the perimeter:
1. 
****
2. 
3. 
4. 
5. 
****
Finito.
The answer for this would be 0.167
