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Flura [38]
3 years ago
5

Jane and Nancy were both awarded National Merit Scholarships (for academic excellence), and both love mathematics. Jane breezed

through Dr. Morgan's calculus class. Thus, Nancy should do well in that class, too."
This argument is:

a. Deductive and Valid
b. Deductive and Invalid
c. Inductive and Strong
d. Inductive and Weak
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
8 0

Answer:

c. Inductive and Strong

Step-by-step explanation:

In inductive reasoning, provided data is analyzed in order to reach a conclusion. In this case, the argument provides data regarding Jane and Nancy's awards and their love for mathematics and then draws a conclusion regarding Nancy's performance in a particular class, this is an example of inductive reasoning.

As for the strength of the argument, it is plausible to infer that Jane and Nancy have similar mathematics skills since they both love calculus and excel academically. Therefore, if Jane does well in the calculus class, it is a strong argument to say that Nancy does as well.

The answer is :

c. Inductive and Strong

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Simplify 6x+(- 9)-9(5x+5)+x
Hatshy [7]

Answer:

Step-by-step explanation:

I've already answered this question.

4 0
3 years ago
Read 2 more answers
A researcher reports survey results by stating that the standard error of the mean is 25 the population standard deviation is 40
bezimeni [28]

Answer:

a) A sample of 256 was used in this survey.

b) 45.14% probability that the point estimate was within ±15 of the population mean

Step-by-step explanation:

This question is solved using the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

a. How large was the sample used in this survey?

We have that s = 25, \sigma = 400. We want to find n, so:

s = \frac{\sigma}{\sqrt{n}}

25 = \frac{400}{\sqrt{n}}

25\sqrt{n} = 400

\sqrt{n} = \frac{400}{25}

\sqrt{n} = 16

(\sqrt{n})^2 = 16^2[tex][tex]n = 256

A sample of 256 was used in this survey.

b. What is the probability that the point estimate was within ±15 of the population mean?

15 is the bounds with want, 25 is the standard error. So

Z = 15/25 = 0.6 has a pvalue of 0.7257

Z = -15/25 = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

45.14% probability that the point estimate was within ±15 of the population mean

3 0
3 years ago
PLEASE ANSWER FAST!!!
Ilya [14]
S= 11/12
15%-p=x
35-$18=n
5 0
3 years ago
Read 2 more answers
13, 5, 4, 9, 7, 14, 4 The deviations are _____.
fenix001 [56]

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean=\frac{sum\;of\;data}{total\;number\;of\;data}

Using the formula

Mean,\mu=\frac{13+5+4+9+7+14+4}{7}

Mean,\mu=\frac{56}{7}=8

Deviation=x_i-\mu

         x_i-\mu

13          5

5           -3

4           - 4

9            1

7             -1

14            6

4            - 4

Hence, option  B is correct.

7 0
3 years ago
A cylindrical container has a base area of 100 m2 and is 12m high. if the container is one-third filled with water, what's the v
docker41 [41]
Volume of water=\frac{1}{3}*BA*H
V=\frac{1}{3} *100 m^{2} *12m
V=400m^{3}
5 0
3 years ago
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