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Reil [10]
3 years ago
15

Chlorine is widely used to purify municipal water supplies and to treat swimming pool water. Suppose that the volume of a partic

ular sample of Cl2 gas is 8.80 L at 890 torr and 23 ∘C. How many grams of Cl2 are in the sample?
Chemistry
1 answer:
Drupady [299]3 years ago
5 0

Answer:

Mass = 30.104 g

Explanation:

Given data:

Volume of Cl₂ = 8.80 L

Pressure = 890 torr (890/760 = 1.17 atm)

Temperature = 23°C (23+273 = 296K)

Mass of chlorine = ?

Solution:

PV = nRT

n = PV/RT

n = 1.17 atm × 8.80 L / 0.0821 atm. L. k⁻¹.mol⁻¹ × 296K

n = 10.296 atm. L / 24.30  atm. L.mol⁻¹

n = 0.424 mol

Mass of chlorine:

Mass = number of moles × molar mass

Mass = 0.424 mol  × 71 g/mol

Mass = 30.104 g

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Answer:

molality of sodium ions is 1.473 m

Explanation:

Molarity is moles of solute per litre of solution

Molality is moles of solute per kg of solvent.

The volume of solution = 1 L

The mass of solution = volume X density = 1000mL X 1.43 = 1430 grams

The mass of solute = moles X molar mass of sodium phosphate = 0.65X164

mass of solute = 106.6 grams

the mass of solvent = 1430 - 106.6 = 1323.4 grams = 1.3234 Kg

the molality = \frac{moles of solute}{mass of solvent in kg}=\frac{0.65}{1.323}= 0.491m

Thus molality of sodium phosphate is 0.491 m

Each sodium phosphate of molecule will give three sodium ions.

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Answer:

[LiOH] = 1.99M

Explanation:

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