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Reil [10]
3 years ago
15

Chlorine is widely used to purify municipal water supplies and to treat swimming pool water. Suppose that the volume of a partic

ular sample of Cl2 gas is 8.80 L at 890 torr and 23 ∘C. How many grams of Cl2 are in the sample?
Chemistry
1 answer:
Drupady [299]3 years ago
5 0

Answer:

Mass = 30.104 g

Explanation:

Given data:

Volume of Cl₂ = 8.80 L

Pressure = 890 torr (890/760 = 1.17 atm)

Temperature = 23°C (23+273 = 296K)

Mass of chlorine = ?

Solution:

PV = nRT

n = PV/RT

n = 1.17 atm × 8.80 L / 0.0821 atm. L. k⁻¹.mol⁻¹ × 296K

n = 10.296 atm. L / 24.30  atm. L.mol⁻¹

n = 0.424 mol

Mass of chlorine:

Mass = number of moles × molar mass

Mass = 0.424 mol  × 71 g/mol

Mass = 30.104 g

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000333 g fluorescein (332.32 g/mol) is dissolved in 225 ml solution of ethanol. the density of ethanol is 0.785 g/ml. what is th
andrey2020 [161]
1) Molarity

M = n / V
n: number of moles of solute
V: volume of the solution in liters

n = mass / molar mass = 0.000333 g / 332.32 g / mol =  1*10 ^ - 6 moles

V = 225 ml * 1 liter / 1000 ml = 0.225 liter

M = 10^-6 mol / 0.225 liter = 0.00000444 M

2) ppm

ppm = parts per million

grams of solute: 0.000333 g

grams of solution = volume * density = 225 ml * 0.785 g / ml = 176.625 g

ppm = [0.00033 g / 176.625 g] * 1,000,000 = 1.868 ppm

 

8 0
3 years ago
Read 2 more answers
Suppose you are a food chemist working for a company that makes and manufactures soda. Your job is to create a new soft drink wi
Mekhanik [1.2K]

Answer:

The answer to your question is given after the questions so I just explain how to get it.

Explanation:

a)

Get the molecular weight of Phosphoric acid

        H₃PO₄ =  (3 x 1) + (31 x 1) + (16 x 4)

                    = 3 + 31 + 64

                    = 98 g

         98 g -----------------  1 mol

      0.045 g ---------------   x

          x = (0.045 x 1) / 98

          x = 0.045 / 98

          x = 0.00046 moles or 4.6 x 10 ⁻⁴

b)

Molarity = \frac{moles}{volume}

Molarity = \frac{0.00046}{0.35}

Molarity = 0.0013 or 1.31 x 10⁻³

c)

Formula            C₁V₁ = C₂V₂

                              V₁ = C₂V₂ / C₁

Substitution

                              V₁ = (0.0013)(1) / 0.01

Simplification and result

                              V₁ = 0.0013 / 0.1

                              V₁ = 0.13 l = 130 ml            

7 0
3 years ago
In which orbital below would an electron (on average) be farthest from the nucleus?
ozzi

Answer:

4f its the last orbital of the above

5 0
3 years ago
Given the lattice energy of NaBr = 736 kJ/mol, the ionization energy of Na = 496 kJ/mol and the electron affinity of Br = −325 k
mars1129 [50]

Answer : The value of \Delta H^o for the reaction is, -565 kJ/mol

Explanation :  

The formation of sodium bromide is,

Na(g)+Br(g)\overset{\Delta H^o}\rightarrow NaBr(s)

\Delta H^o = enthalpy of the reaction

The steps involved in the reaction are:

(1) Conversion of gaseous sodium atoms into gaseous sodium ions.

Na(g)\overset{\Delta H_I}\rightarrow Na^{+1}(g)

\Delta H_I = ionization energy of sodium = 496 kJ/mol

(2) Conversion of gaseous bromine atoms into gaseous bromine ions.

Br(g)\overset{\Delta H_E}\rightarrow Br^-(g)

\Delta H_E = electron affinity energy of bromine = -325 kJ/mol

(3) Conversion of gaseous cations and gaseous anion into solid sodium bromide.

Na^+(g)+Br^-(g)\overset{\Delta H_L}\rightarrow NaBr(s)

\Delta H_L = lattice energy of sodium bromide = -736 kJ/mol

To calculate the \Delta H^o for the reaction, the equation used will be:

\Delta H^o=\Delta H_I+\Delta H_E+\Delta H_L

Now put all the given values in this equation, we get:

\Delta H^o=496kJ/mole+(-325kJ/mole)+(-736kJ/mole)

\Delta H^o=-565kJ/mole

Therefore, the value of \Delta H^o for the reaction is, -565 kJ/mol

7 0
3 years ago
URGENT!!-- Please help!
blondinia [14]

Moles of gas = 0.369

<h3>Further explanation</h3>

Given

P = 2 atm

V = 5.3 L

T = 350 L

Required

moles of gas

Solution

Ideal gas Law

\tt n=\dfrac{PV}{RT}\\\\n=\dfrac{2\times 5.3}{0.082\times 350}\\\\n=0.369

Avogadro's law : at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

moles of O₂ = 45% x 0.369 = 0.166

moles of Ar = 12% x 0.369 = 0.044

moles of N = 43% x 0.369 = 0.159

3 0
3 years ago
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