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IrinaK [193]
3 years ago
15

Two boys on bicycles start from the same place and ride in opposite directions. One ndes

Mathematics
1 answer:
nata0808 [166]3 years ago
6 0
The sum of their speeds is (27/3) = 9 km/h.

One of them goes at 3 kmh and the other goes at 6kmh
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In this figure, the distance from A to B is 10 units. The distance from B to X is 10 units. What else is true? 
evablogger [386]
I believe it would be a to X is 20 units because A to B is 10 units so a to X would make sense if it was 20 units hope this helps!
6 0
3 years ago
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PLEASE HELP. TAKE AT HOME TEST. if u = LN5 and v = LN2, write LN8/15 in terms of u and v. (8/15 is 8 over 25)
astra-53 [7]

Answer:

\ln( \frac{8}{25} )  = 3v  -  2u

Step-by-step explanation:

We have that

u=  \ln(5)

and

v =  \ln2

This implies that;

5 =  {e}^{u}

and

2 =  {e}^{v}

Now find and expresion for

\ln( \frac{8}{25} )

Which is

\ln( \frac{8}{25} )  =  ln(8)  -  ln(25)

\ln( \frac{8}{25} )  =  ln( {2}^{3} )  -  ln(  {5}^{2} )

\ln( \frac{8}{25} )  = 3 ln( {2} )  -  2ln(5)

\ln( \frac{8}{25} )  = 3v  -  2u

8 0
3 years ago
Calculate:<br><br> 5,500 milliliters(mL) =__liters (L)
schepotkina [342]

Answer:

5.5 liters

Step-by-step explanation: there are 1000 milliliters in a liter, so divide 5,500/1000

8 0
3 years ago
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4x+2y=-8 <br>3x-2y=22<br>x=<br>y=​
BaLLatris [955]

This should be the answer and I showed you how to do it

(X,Y), ( 2,-8)

3 0
3 years ago
Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank
mars1129 [50]

Complete question:

Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.

Answer:

11/288

Step-by-step explanation:

We are given:

Box 1: ( 4White, ORed)

Box 2: (3White, 1Red)

Box 3: (2White, 2 Red)

We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.

Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.

Our Event, E = getting 2 red balls.

Now Box 1 is ruled out, we have:

P[E(B1)]= 0

P[E/B3)] = (2 2) / (4 2)

= 1/6

If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:

P(E/B2) = (1/4) *(1/4)

= 1/16

Therefore probability that 2 balls extracted are red, we have:

P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 0 * \frac{1}{3} + \frac{1}{6}*\frac{1}{3} + \frac{1}{16}*\frac{1}{3}

= 11/288

3 0
3 years ago
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