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vlada-n [284]
3 years ago
8

Reflect the point (8,0) across the y-axis

Mathematics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:-8,0

Step-by-step explanation:

Ilya [14]3 years ago
7 0

after the the reflection over the y-axis (-8,0)

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Need help finding the area of the shaded region. Round to the nearest tenth. Need help ASAP
Sergio [31]

Answer:   294.4 m²

<u>Step-by-step explanation:</u>

Separate the shaded region into two parts:

  1. The section containing the central angle of 230° (360° - 130°)
  2. The triangle with sides 11.1, 11.1 & 20.12 (use Law of Cosines)

1.\ Area(A)=\pi\ r^2\ \bigg(\dfrac{\theta}{360}\bigg)\\\\\\.\qquad \qquad =\pi(11.1)^2\bigg(\dfrac{230}{360}\bigg)\\\\\\.\qquad \qquad =247.3

2.\ \text{Use Law of cosines to find the length of the third side.}\\\text{ Then use Heron's formula to find the Area of the triangle.}\\\\s=\dfrac{11.1+11.1+20.12}{2}=21.16\\\\\\A=\sqrt{s(s-a)(s-b)(s-c)}\\\\.\ =\sqrt{21.16(21.16-11.1)(21.16-11.1)(21.16-20.12)}\\\\.\ =\sqrt{2227}\\\\.\ =47.1

Area of shaded region = Area of (1) + Area of (2)

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Evaluating integral by net area
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The graph of g(x)=\sqrt{64-x^2} is the upper half of a circle with radius \sqrt{64}=8. It's symmetric about x=0, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is \frac{\pi 8^2}4=16\pi.

Then use the fact that the definite integral is distributive over sums, meaning

\displaystyle\int_0^8f(x)+g(x)\,\mathrm dx=\int_0^8f(x)\,\mathrm dx+\int_0^8g(x)\,\mathrm dx=16+16\pi

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