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Contact [7]
3 years ago
9

When a system does work, what happens to its internal energy

Physics
2 answers:
tester [92]3 years ago
8 0
The first law, which deals with changes in the internal energy, thus becomes 0 = Q - W, so Q = W.

If the system does work, the energy comes from heat flowing into the system from the reservoir; if work is done on the system, heat flows out of the system to the reservoir
Ipatiy [6.2K]3 years ago
8 0

Answer:

Internal energy decreases

Explanation:

According to first law of thermodynamics heat can neither be created nor destroyed , but it changes from one form to another form.

Mathematical representation :

U=Q-w

Where U=Internal energy of system

w=Work done

Q=Heat gain or removed

When system does work then it take positive .When system does work then Q is positive .

Hence, the internal energy will decrease .

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Different ____ of light through two separate mediums causes the bending of waves fronts associated with light rays.
Fittoniya [83]

Different speeds of light through two separate media ... and the difference in wavelength caused by the difference ... causes the bending of waves fronts associated with light rays.

AFTER the bend, since the light rays then travel in a different direction, we may also say that the 'velocity' has changed.

8 0
3 years ago
a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km​
mixas84 [53]
The body will take 20 seconds to cover a distance of 1000 m i.e. 1 km
7 0
3 years ago
Read 2 more answers
A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos
Andreas93 [3]

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

x" = -6 + 5

x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

brainly.com/question/17587058

3 0
3 years ago
B) A skilled jet fighter flies a stunt plane in a vertical circle of 1200 ft
vodka [1.7K]

Answer:I need the ans to this one too

Explanation:

4 0
3 years ago
A 5.00-m-long uniform ladder, weighing 200 N, rests against a smooth vertical wall with its base on a horizontal rough floor, a
Morgarella [4.7K]

Answer:

0.488  m  

Explanation:

If θ be the angle ladder makes with the plane

cos θ = 1.2 / 5

Tan θ = 4.04

Let the height a person of weight 600 N  can climb be h from the ground .

Distance from the base point  where ladder touches the floor  = h / tanθ

= h / 4.04

Total reaction force = total downward force

R = 200 + 600

800 N

Frictional force = μ R

= .2 x 800

= 160 N

Taking moment of force about the point on the ladder  where it  touches the floor  and balancing them

200 x 1.2 x .5 + 600 x   h / tanθ  = μ R x  1.2 / tanθ ( reaction  at the top point of ladder where it touches the wall is  R₁ and

R₁ =μ R   )

= 200 x 1.2 x .5 + 600 x   h / tanθ  = 160 x 1.2 / tanθ

120  - 600 h / 4.04 = 47.52

120 - 47.52 = 600 h / 4.04

72.48= 148.51 h

h = 0.488  m  

=

5 0
3 years ago
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