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kupik [55]
3 years ago
7

Modeling Nuclear changes

Chemistry
1 answer:
alina1380 [7]3 years ago
7 0
Whats the question?...
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Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is comple
MariettaO [177]

Answer:

1. Helper T cell is one of the T cells that absence results in no immune response.

2. Cytotoxic T cell is also a type of white blood cell that Kills cancer cells and virus infected body cells.

3. Regulatory T cell is a suppressor T cells that slows or stops the immune response.

4. Memory cell is a type of B cell that enables quick and efficient response to secondary exposure to antigen

5. B cell is a cell that forms antibody producing cells

5 0
3 years ago
HALP ME PLEZ.
zzz [600]
The answer is B. Flammability 
7 0
4 years ago
Read 2 more answers
A chemist prepares a solution of silver(II) oxide by measuring out 0.0013 of silver(II) oxide into a 100 mL volumetric flask and
azamat

Answer:

1.3x10⁻⁸ mol/L

Explanation:

<em>0.0013μmol, Calculate concentration in mol/L</em>

<em />

To obtain concentration in mol/L we need to convert the μmoles to moles and mL to liters:

<em>Moles silver(II) oxide:</em>

0.0013μmol × (1mol / 1x10⁶μmol) = 1.3x10⁻⁹ moles

<em>Liters solution:</em>

100mL * (1L / 1000mL) = 0.1L

That means concentration in mol/L is:

1.3x10⁻⁹ moles / 0.1L =

<h3>1.3x10⁻⁸ mol/L</h3>
6 0
3 years ago
The value of Ksp for PbCl2 is 1.6 ×10-5. What is the lowest concentration of Cl-(aq) that would be needed to begin precipitation
Dovator [93]

Answer:

0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

Explanation:

Concentration of lead nitarte = [Pb(NO_3)_2]=0.010 M

Pb(NO_3)_2(aq)\rightleftharpoons Pb^{2+}(aq)+2NO_{3}^{-}(aq0

1 Mole of lead nirate gives 1 mole of lead ion.

Concentration of lead ion in the solution = 1\times 0.010 M= 0.010 M

Pb(Cl)_2(aq)\rightleftharpoons  Pb^{2+}(aq)+2Cl^{-}(aq0

Concentration of chloride ions = [Cl^-]

The value of K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}

K_{sp}=[Pb^{2+}][Cl^{-}]^2

1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2

[Cl^-]=0.04 M

0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

3 0
4 years ago
Use the following equation to complete the questions below. 2C2H6 + 7O2 → 4CO2 + 6H2O How many moles of oxygen would you need to
worty [1.4K]
43.75 moles of oxygen and 27.42 moles of water.

4 0
3 years ago
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