Answer:
Carboxylic acids produce hydrogen bonds amongst themselves and possess lower vapor pressure. They generally possess a sour odor. When an acid and a base react with each other to produce salt and water and comprises the combination of hydrogen and hydroxide ions, the reaction is termed the neutralization reaction. Thus, when carboxylic acid reacts with base the reaction is termed neutralization.
On the other hand, esters are known for their pleasant fragrances. They do not produce hydrogen bonds amongst themselves and possess higher vapor pressure. A hydration reaction in which free hydroxide dissociates the ester bonds between the glycerol and fatty acids of a triglyceride, leading to the formation of free fatty acids and glycerol is termed saponification.
Thus, the given blanks can be filled with carboxylic acid, carboxylic acid, esters, esters, esters, and carboxylic acid.
Answer:<span> a) the process for the first ionization energy
</span>
<span>Every time you take a electron you're requiring more and more energy. Expelling the first one
will require less energy than expelling the second and the second will
require less than the third, and so on.
When you take the first one, the atom becomes positive and with that the negative forces of the electron will be more attracted to the positive
charge. The more electrons that are lost, the
more positive this ion will become, causing it to be more difficult to separate the
electrons from the atom.
</span>
Answer:
An oxyacetylene torch can also be used for welding. When welding with an oxyacetylene torch, the flame is used to produce molten metal along the edge of two work pieces.
hope this helped
if you want plz give brainliest to help you more
Answer:
It will decrease by 2 units.
Explanation:
The Henderson-Hasselbalch equation for a buffer is
pH = pKa + log(base/acid)
Let's assume your acid has pKa = 5.
(a) If the base: acid ratio is 1:1,
pH(1) = 5 + log(1/1) = 5 + log(1) = 5 + 0 = 5
(b) If the base: acid ratio is 1:100,
pH(2) = 5 + log(1/100) = 5 + log(0.01) = 5 - 2 = 3
(c) Difference
ΔpH = pH(2) - pH(1) = 5 - 3 = -2
If you increase the acid:base ratio to 100:1, the pH will decrease by two units.
Answer:
9.4
Explanation:
The equation for the reaction can be represented as:
+ 
⇄ 
The ICE table can be represented as:
+ 
⇄
Initial 0.27 0.49 0.0
Change -x -2x x
Equilibrium 0.27 - x 0.49 -2x x
We can now say that the concentration of at equilibrium is x;
Let's not forget that at equilibrium = 0.11 M
So:
x = [] = 0.11 M
[] = 0.27 - x
[] = 0.27 - 0.11
[] = 0.16 M
[] = (0.49 - 2x)
[] = (0.49 - 2(0.11))
[] = 0.49 - 0.22
[] = 0.27 M
![K_C = \frac{[CH_3OH]}{[CO][H_2]^2}](https://tex.z-dn.net/?f=K_C%20%3D%20%5Cfrac%7B%5BCH_3OH%5D%7D%7B%5BCO%5D%5BH_2%5D%5E2%7D)
= 9.4
∴ The equilibrium constant at that temperature = 9.4
