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mel-nik [20]
2 years ago
14

Is science logical please help meeeeeee

Chemistry
2 answers:
bekas [8.4K]2 years ago
7 0
Yes science is logical
atroni [7]2 years ago
6 0

Answer:

It kind of is logical so my answer is yes

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2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

4 0
3 years ago
How is thermal energy transferred between two objects that are at different temperatures?
qwelly [4]

Answer:

heat flows from the object that has more thermal more energy to the object with less thermal energy

8 0
3 years ago
HELP ME IK YOU GUYS ARE HELLA SMART
Bad White [126]

Answer:

1.200g

Explanation:

At the top it's 0 and that scale goes by 10s

The middle scale is 1 and it goes by 1s

The bottom scale is .2 and it goes by .1s

1+.2= 1.2 the extra zeroes are just place holders

1.200g

5 0
2 years ago
What is the ph of a 0.014 M HCL solution?
Allushta [10]

Answer:

pH = 1.853

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

[H_3O^+] = [HCl] = 0.014

pH  = -log [H^+] = -log [H_3O^+]

Substituting the available values in above equation, we can say that   the pH of the solution is equal to

- log (0.014)

pH = 1.853

pH of a 0.014 M HCL solution = 1.853

8 0
3 years ago
To prevent poisoning, what three items should NEVER be taken into the lab?
Roman55 [17]

The answer of this answer is given in the attached file

Download pdf
7 0
3 years ago
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