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kykrilka [37]
2 years ago
14

The WSJ lists a bond as Acme 9s13 and the price as 89.875. If your required rate of return is 10%, would you buy one of these bo

nds in 2001?
Mathematics
1 answer:
Blizzard [7]2 years ago
4 0

Answer :

Yes

Explanation :

A bond in finance may be defined as an instrument of the indebtedness of a bond. It is a fixed income instrument that shows a loan by investors. Bonds may be in mutual funds or in private funding.

Here in the question it is given that WSJ is a company and it listed a bond on the market as Acme 9s13.

The price of the bond 89.875

The rate of return rate will be = 10%

So I will buy the bond of WSJ in the year 2001 as it will give a return of $ 931.00

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June and Armando are each in a hot air balloon. Armando's balloon is at a slightly higher elevation than June's. The two balloon
Mandarinka [93]

Answer:

46.63 ft

Step-by-step explanation:

I've drawn and attached a triangle diagram to represent this elevation and distance of balloons.

Now, from the diagram attached, we can see the angle at which June must look up to see Armando is 25°.

Also, the height of Armando above June is represented by "x".

Thus, using pythagoras theorem, we can find x.

Thus;

x/100 = tan 25

x = 100 × tan 25

x = 100 × 0.4663

x = 46.63 ft

6 0
3 years ago
What is the least common multiple of 16 and 22?
hammer [34]

Answer:

the answer is 176 hope this helps

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
50 POINTS AND BRAINLIEST!!! NEED HELP NOW!!
Ad libitum [116K]

1. would have to be team E because add up all the numbers 1058/8 (which is how many numbers that is there) 132.25.

2. (More of an explanation if you still don't understand)

52+52+53+54+55+55=321/6=53.5

52+53+54+55+57+57=328/6=54.66 repeated rounded to 54.7 so your answer is 1.2

3 0
2 years ago
A certain square is to be drawn on a coordinate plane. One of the vertices must be on the origin, and the square is to have an a
Scrat [10]

Answer:

The answer is (C) 8

Step-by-step explanation:

First, let's calculate the length of the side of the square.

A_{square}=a^2, where a is the length of the side. Now, let's try to build the square. First we need to find a point which distance from (0, 0) is 10. For this, we can use the distance formula in the plane:

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} which for x_1=0 and y_1 = 0 transforms as  d=\sqrt{(x_2)^2 + (y_2)^2}. The first point we are looking for is connected to the origin and therefore, its components will form a right triangle in which, the Pythagoras theorem holds, see the first attached figure. Then, x_2, y_2 and 10 are a Pythagorean triple. From this, x_2= 6 or  x_2=8 while y_2= 6 or y_2=8. This leads us with the set of coordinates:

(\pm 6, \pm 8) and (\pm 8, \pm 6).  (A)

The next step is to find the coordinates of points that lie on lines which are perpendicular to the lines that joins the origin of the coordinate system with the set of points given in (A):

Let's do this for the point (6, 8).

The equation of the line that join the point (6, 8) with the origin (0, 0) has the equation y = mx +n, however, we only need to find its slope in order to find a perpendicular line to it. Thus,

m = \frac{y_2-y_1}{x_2-x_1} \\m =  \frac{8-0}{6-0} \\m = 8/6

Then, a perpendicular line has an slope m_{\bot} = -\frac{1}{m} = -\frac{6}{8} (perpendicularity condition of two lines). With the equation of the slope of the perpendicular line and the given point (6, 8), together with the equation of the distance we can form a system of equations to find the coordinates of two points that lie on this perpendicular line.

m_{\bot}=\frac{6}{8} = \frac{8-y}{6-x}\\ 6(6-x)+8(8-y)=0  (1)

d^2 = \sqrt{(y_o-y)^2+(x_o-x)^2} \\(10)^2=\sqrt{(8-y)^2+(6-x)^2}\\100 = \sqrt{(8-y)^2+(6-x)^2}   (2)

This system has solutions in the coordinates (-2, 14) and (14, 2). Until here, we have three vertices of the square. Let's now find the fourth one in the same way we found the third one using the point (14,2). A line perpendicular to the line that joins the point (6, 8) and (14, 2) has an slope m = 8/6 based on the perpendicularity condition. Thus, we can form the system:

\frac{8}{6} =\frac{2-y}{14-x} \\8(14-x) - 6(2-y) = 0  (1)

100 = \sqrt{(14-x)^2+(2-y)^2}  (2)

with solution the coordinates (8, -6) and (20, 10). If you draw a line joining the coordinates (0, 0), (6, 8), (14, 2) and (8, -6) you will get one of the squares that fulfill the conditions of the problem. By repeating this process with the coordinates in (A), the following squares are found:

  • (0, 0), (6, 8), (14, 2), (8, -6)
  • (0, 0), (8, 6), (14, -2), (6, -8)
  • (0, 0), (-6, 8), (-14, 2), (-8, -6)
  • (0, 0), (-8, 6), (-14, -2), (-6, -8)

Now, notice that the equation of distance between the two points separated a distance of 10 has the trivial solution (\pm10, 0) and  (0, \pm10). By combining this points we get the following squares:

  • (0, 0), (10, 0), (10, 10), (0, 10)
  • (0, 0), (0, 10), (-10, 10), (-10, 0)
  • (0, 0), (-10, 0), (-10, -10), (0, -10)
  • (0, 0), (0, -10), (-10, -10), (10, 0)

See the attached second attached figure. Therefore, 8 squares can be drawn  

8 0
2 years ago
Find the area of figure 1.<br><br> a -12 units2<br> b- 14 units2<br> c- 8 units2<br> d- 10 units2
Brilliant_brown [7]

Answer:

D

Step-by-step explanation:

if you look at the chart. it goes up five and has a width of 2. multiply 5 x 2 = you get 10

3 0
2 years ago
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