Help please I’m really struggling

Evaluate 6a + 4 when a=1/3

ozzi

Answer:

6

Step-by-step explanation:

6 x 1/3 = 2

2 + 4 = 6

- Hope this helps! If you would like further help on this please let me know.

3 0

3 years ago

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If a train was traveling at 80 mph to the next station and it arrived 6 hours later, how far the train travel to get to the stat

Vikki [24]

Answer:

80 x 6 =480

Step-by-step explanation:

7 0

2 years ago

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Find an equation of the line parallel to −5x+7y=3 that passes through the point (9,−4). If possible, write the equation in slope

saul85 [17]

From the original equation we have:

$-5x+7y=3$ $7y=5x+3$ $y=\frac{5}{7}x+\frac{3}{7}$

The slope of this line is 5/7 and for the new equation to be parallel to the original must have the same slope, and using the point-slope formula we have:

$y-(-4)=\frac{5}{7}(x-9)$ $y+4=\frac{5}{7}x-\frac{45}{7}$ $y=\frac{5}{7}x-\frac{45}{7}-4$ $y=\frac{5}{7}x-\frac{73}{7}$

7 0

1 year ago

A research group is curious about their city’s participation in flu shot clinics. They suspect that there is a difference betwee

Kipish [7]

Answer:

$t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505$

$p_v =2*P(t_{40}>0.505)=0.61633$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=162$ represent the mean for sample of clinic attendees

$\bar X_{2}=156$ represent the mean for the sister city

$s_{1}=41$ represent the sample standard deviation for 1

$s_{2}=36$ represent the sample standard deviation for 2

$n_{1}=22$ sample size for the group 2

$n_{2}=20$ sample size for the group 2

$\alpha=0.05$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=22+20-2=40$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(162-156)-0}{\sqrt{\frac{41^2}{22}+\frac{36^2}{20}}}}=0.505$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{40}>0.505)=0.61633$

Comparing the p value with the significance level $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, then the difference between the two groups is NOT significantly different.

3 0

3 years ago

HELPPPPPPPPPPPP PLEASEEEEEEEE

Olegator [25]

Answer:

1/1 or 1

Step-by-step explanation:

1. Find two points from the graph

2. Set them in the slope formula ( $\frac{y^2- y^1}{x^2 - x^1}$ )

3. Insert the coordinates into this formula

Points: (0,1) and (1, 2)

2 -1 = 1

1 - 0 = 1

1/1 = 1

3 0

3 years ago