How much water will be required to dissolve 0.3g of benzoic acid at 95oC given that the solubility of BA at 95oC is 68.0g/L?

1 answer:

6 0

Write as a proportion, showing the relationship of both given information:
68.0g 0.3g
---------- = -----------
1L x ( your answer)

Cross multiply: 68.0g× X = 0.3g × 1L
68.0g (X)= 0.3g/L
Solve for X by dividing both sides by 68.0 g
68.0g (X) = 0.3g/L
------------- ------------------
68.0g 68.0g

Then enter into calculator 0.3/68 and that will be your solution. Make sure you round up.

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