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madreJ [45]
3 years ago
11

Which of the following statements about the greenhouse effect is false?

Chemistry
2 answers:
CaHeK987 [17]3 years ago
7 0
Your answer is D, I go to keystone too 
Nataly_w [17]3 years ago
3 0
The answer is a ik for a fact
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Answer:

B: it allow quick conversation to others

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3 years ago
Enter a balanced nuclear equation for the production of lead-212, used in the treatment of some cancers, from the beta decay of
MariettaO [177]

Answer:

\frac{212}{81}Tl ------>\beta  + \frac{212}{82}Pb

Explanation:

Beta emission involves the conversion of a neutron to a proton, an electron and a neutrino. This leads to a reduction in the neutron-proton ratio.

During a beta emission, the mass number of the parent and daughter nuclei remain the same. The atomic number of the daughter nucleus increases by one unit above that of the parent nucleus as we can see from the equation.

Hence, the daughter nucleus is found one place after its parent in the periodic table.

8 0
3 years ago
What steps are involved in the process that turns sediment back to rock? Select all that apply.
jeyben [28]

Answer:

compaction and cementation

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4 0
3 years ago
Read 2 more answers
Why do single cell organisms divide?
mixer [17]
Single-celled organisms<span> which use asexual reproduction can </span>do<span> so very rapidly simply by </span>dividing<span> into two equal halves. This is called binary fission. In yeasts the </span>cell<span> does not </span>divide<span> equally in two halves; instead, there is a large mother </span>cell<span> and a smaller daughter </span>cell<span>. This is called budding.</span>
7 0
3 years ago
If 650. grams of C6H12O6 (FW 180.16) reacts with 650. grams of O2 (FW 32.00) in cellular respiration: C6H12O6 6 O2 --&gt; 6 CO2
cestrela7 [59]

Answer:

O2 is limiting reactant

Explanation:

To find the limiting reactant we need to convert the mass of each reactant to the moles using the formula weight. And, as 1 mole of C6H12O6 reacts with 6 moles of O2, we can know wich reactant will be over first (Limiting reactant) as follows:

<em>Moles C6H12O6:</em>

650g * (1mol/180.16g) = 3.608 moles C6H12O6

<em>Moles O2:</em>

650g * (1mol/32g) = 20.31 moles O2

Now, for a complete reaction of 3.608 moles of C6H12O6 are required:

3.608 moles C6H12O6 * (6mol O2 / 1mol C6H12O6) = 21.65 moles O2

As there are just 20.31 moles of O2,

<h3>O2 is limiting reactant</h3>
4 0
3 years ago
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