I got on here because I don't understand the question but I did my best to answer because I noticed you asked 3 days ago. IF I'm right the answer is D. My diagram shows
A at -50 °C
B at 0 °C
C at 50 °C
D at 100 °C (gas to liquid or liquid to gas)
And E at 150 °C
So I hope I'm right because I'm answering the same question.
The volume of 0.20 moles of helium at STP is 4.5 liters.
Explanation:
Given:
Number of moles = 0.20 moles
To Find:
The volume of Helium at STP =?
Solution:
According to ideal gas law
PV = nRT
where
P is pressure,
V is volume,
n is the number of moles
R is the gas constant, and
T is temperature in Kelvin.
The question already gives us the values for p and T
,because helium is at STP. This means that temperature is 273.15 K and pressure is 1 atm
.
We also already know the gas constant. In our case, we'll use the value of
0.08206 L atm/K mol since these units fit the units of our given values the best
On substituting these values we get



V = 4.5 Liters
Answer:
<h2>3.31 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula

From the question
mass = 23.2 g
volume = final volume of water - initial volume of water
volume = 62 - 55 = 7 mL
We have

We have the final answer as
<h3>3.31 g/mL</h3>
Hope this helps you
Reducing the volume of contained gas by one third, while holding temperature constant, causes pressure to D. be increased by one third